Python - re.findall returns unwanted result

Solution 1:

>>> re.findall("(?:100|[0-9][0-9]|[0-9])%", "89%")
['89%']

When there are capture groups findall returns only the captured parts. Use ?: to prevent the parentheses from being a capture group.

Solution 2:

The trivial solution:

>>> re.findall("(100%|[0-9][0-9]%|[0-9]%)","89%")
['89%']

More beautiful solution:

>>> re.findall("(100%|[0-9]{1,2}%)","89%")
['89%']

The prettiest solution:

>>> re.findall("(?:100|[0-9]{1,2})%","89%")
['89%']

Solution 3:

Use an outer group, with the inner group a non-capturing group:

>>> re.findall("((?:100|[0-9][0-9]|[0-9])%)","89%")
['89%']