Displaying a number in Indian format using Javascript
I have the following code to display in Indian numbering system.
var x=125465778;
var res= x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
Am getting this output :125,465,778
.
I need output like this: 12,54,65,778
.
Please help me to sort out this problem .
i'm late but i guess this will help :)
you can use Number.prototype.toLocaleString()
Syntax
numObj.toLocaleString([locales [, options]])
var number = 123456.789;
// India uses thousands/lakh/crore separators
document.getElementById('result').innerHTML = number.toLocaleString('en-IN');
// → 1,23,456.789
document.getElementById('result1').innerHTML = number.toLocaleString('en-IN', {
maximumFractionDigits: 2,
style: 'currency',
currency: 'INR'
});
// → ₹1,23,456.79
<div id="result"></div>
<div id="result1"></div>
For Integers:
var x=12345678;
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree;
alert(res);
Live Demo
For float:
var x=12345652457.557;
x=x.toString();
var afterPoint = '';
if(x.indexOf('.') > 0)
afterPoint = x.substring(x.indexOf('.'),x.length);
x = Math.floor(x);
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree + afterPoint;
alert(res);
Live Demo
Simple way to do,
1. Direct Method using LocalString()
(1000.03).toLocaleString()
(1000.03).toLocaleString('en-IN') # number followed by method
2. using Intl - Internationalization API
The Intl object is the namespace for the ECMAScript Internationalization API, which provides language sensitive string comparison, number formatting, and date and time formatting.
eg: Intl.NumberFormat('en-IN').format(1000)
3. Using Custom Function:
function numberWithCommas(x) {
return x.toString().split('.')[0].length > 3 ? x.toString().substring(0,x.toString().split('.')[0].length-3).replace(/\B(?=(\d{2})+(?!\d))/g, ",") + "," + x.toString().substring(x.toString().split('.')[0].length-3): x.toString();
}
console.log("0 in indian format", numberWithCommas(0));
console.log("10 in indian format", numberWithCommas(10));
console.log("1000.15 in indian format", numberWithCommas(1000.15));
console.log("15123.32 in indian format", numberWithCommas(15123.32));
if your input is 10000.5,
numberWithCommas(10000.5)
You will get output like this, 10,000.5
For integers only no additional manipulations needed.
This will match every digit from the end, having 1 or more double digits pattern after, and replace it with itself + ",":
"125465778".replace(/(\d)(?=(\d\d)+$)/g, "$1,");
-> "1,25,46,57,78"
But since we want to have 3 in the end, let's state this explicitly by adding extra "\d" before match end of input:
"125465778".replace(/(\d)(?=(\d\d)+\d$)/g, "$1,");
-> "12,54,65,778"