Compare two arrays with the same value but with a different order

You can use NSCountedSet for that purpose:

- (BOOL)isSameValues:(NSArray*)array1 and:(NSArray*)array2
{
    NSCountedSet *set1 = [NSCountedSet setWithArray:array1];
    NSCountedSet *set2 = [NSCountedSet setWithArray:array2];
    return [set1 isEqualToSet:set2];
}

NSCountedSet is a collection of different objects, where each object has an associated counter with it. Therefore the result for

NSArray *array1 = @[@0,@1,@2,@3];
NSArray *array2 = @[@2,@3,@1,@0];

is YES, but for

NSArray *array1 = @[@1,@1,@3,@3];
NSArray *array2 = @[@3,@3,@3,@1];

the result is NO.

Update: this will not work if arrays have duplicate elements!

You could create two NSSets with those arrays and the compare them.

NSArray * array1 = @[@0,@1,@2,@3];
NSArray * array2 = @[@2,@3,@1,@0];

NSSet *set1 = [NSSet setWithArray:array1];
NSSet *set2 = [NSSet setWithArray:array2];

NSLog(@"result %@", [set1 isEqualToSet:set2] ? @"YES" : @"NO");

if ([[NSSet setWithArray:array1] isEqualToSet:[NSSet setWithArray:array2]]) {
    // the objects are the same
}