Using AJAX to pass variable to PHP and retrieve those using AJAX again

Solution 1:

Use dataType:"json" for json data

$.ajax({
     url: 'ajax.php', //This is the current doc
     type: "POST",
     dataType:'json', // add json datatype to get json
     data: ({name: 145}),
     success: function(data){
         console.log(data);
     }
});  

Read Docs http://api.jquery.com/jQuery.ajax/

Also in PHP

<?php
  $userAnswer = $_POST['name']; 
  $sql="SELECT * FROM <tablename> where color='".$userAnswer."'" ;
  $result=mysql_query($sql);
  $row=mysql_fetch_array($result);
  // for first row only and suppose table having data
  echo json_encode($row);  // pass array in json_encode  
?>

Solution 2:

No need to use second ajax function, you can get it back on success inside a function, another issue here is you don't know when the first ajax call finished, then, even if you use SESSION you may not get it within second AJAX call.

SO, I recommend using one AJAX call and get the value with success.

example: in first ajax call

    $.ajax({
        url: 'ajax.php', //This is the current doc
        type: "POST",
        data: ({name: 145}),
        success: function(data){
            console.log(data);
            alert(data);
            //or if the data is JSON
            var jdata = jQuery.parseJSON(data);
        }
    }); 

Solution 3:

$(document).ready(function() {
    $("#raaagh").click(function() {
        $.ajax({
            url: 'ajax.php', //This is the current doc
            type: "POST",
            data: ({name: 145}),
            success: function(data) {
                console.log(data);
                $.ajax({
                    url:'ajax.php',
                    data: data,
                    dataType:'json',
                    success:function(data1) {
                        var y1=data1;
                        console.log(data1);
                    }
                });
            }
        });
    });
});

Use like this, first make a ajax call to get data, then your php function will return u the result which u wil get in data and pass that data to the new ajax call

Solution 4:

In your PhP file there's going to be a variable called $_REQUEST and it contains an array with all the data send from Javascript to PhP using AJAX.

Try this: var_dump($_REQUEST); and check if you're receiving the values.