string comparison in batch file

Solution 1:

Just put quotes around the Environment variable (as you have done) :
if "%DevEnvDir%" == "C:\Program Files (x86)\Microsoft Visual Studio 10.0\Common7\IDE\"
but it's the way you put opening bracket without a space that is confusing it.

Works for me...

C:\if "%gtk_basepath%" == "C:\Program Files\GtkSharp\2.12\" (echo yes)
yes

Solution 2:

While @ajv-jsy's answer works most of the time, I had the same problem as @MarioVilas. If one of the strings to be compared contains a double quote ("), the variable expansion throws an error.

Example:

@echo off
SetLocal

set Lhs="
set Rhs="

if "%Lhs%" == "%Rhs%" echo Equal

Error:

echo was unexpected at this time.

Solution:

Enable delayed expansion and use ! instead of %.

@echo off
SetLocal EnableDelayedExpansion

set Lhs="
set Rhs="

if !Lhs! == !Rhs! echo Equal

:: Surrounding with double quotes also works but appears (is?) unnecessary.
if "!Lhs!" == "!Rhs!" echo Equal

I have not been able to break it so far using this technique. It works with empty strings and all the symbols I threw at it.

Test:

@echo off
SetLocal EnableDelayedExpansion

:: Test empty string
set Lhs=
set Rhs=
echo Lhs: !Lhs! & echo Rhs: !Rhs!
if !Lhs! == !Rhs! (echo Equal) else (echo Not Equal)
echo.

:: Test symbols
set Lhs= \ / : * ? " ' < > | %% ^^ ` ~ @ # $ [ ] & ( ) + - _ =
set Rhs= \ / : * ? " ' < > | %% ^^ ` ~ @ # $ [ ] & ( ) + - _ =
echo Lhs: !Lhs! & echo Rhs: !Rhs!
if !Lhs! == !Rhs! (echo Equal) else (echo Not Equal)
echo.