How will a C# switch statement's default label handle a nullable enum?
Solution 1:
If it's null, it will hit the default label.
public enum YesNo
{
Yes,
No,
}
public class Program
{
public static void Main(string[] args)
{
YesNo? value = null;
switch (value)
{
case YesNo.Yes:
Console.WriteLine("Yes");
break;
case YesNo.No:
Console.WriteLine("No");
break;
default:
Console.WriteLine("default");
break;
}
}
}
The program will print default
.
Unless null is handled.
public class Program
{
public static void Main(string[] args)
{
YesNo? value = null;
switch (value)
{
case YesNo.Yes:
Console.WriteLine("Yes");
break;
case YesNo.No:
Console.WriteLine("No");
break;
case null:
Console.WriteLine("NULL");
break;
default:
Console.WriteLine("default");
break;
}
}
}
prints NULL
.
If you have an unhandled enum value that was added later:
public enum YesNo
{
Yes,
No,
FileNotFound,
}
public class Program
{
public static void Main(string[] args)
{
YesNo? value = YesNo.FileNotFound;
switch (value)
{
case YesNo.Yes:
Console.WriteLine("Yes");
break;
case YesNo.No:
Console.WriteLine("No");
break;
default:
Console.WriteLine("default");
break;
}
}
}
It still prints default
.
Solution 2:
You can use the null-coalescing operator ??
to route null
switch values to a specific case label other than default
:
public static IEnumerable<String> AsStrings(this IEnumerable<Char[]> src)
{
Char[] rgch;
var e = src.GetEnumerator();
while (e.MoveNext())
{
switch ((rgch = e.Current)?.Length ?? -1)
{
case -1: // <-- value when e.Current is 'null'
yield return null;
break;
case 0:
yield return String.Empty;
break;
case 1:
yield return String.Intern(new String(rgch[0], 1));
break;
default: // 2...n
yield return new String(rgch);
break;
}
}
}