Initialization Order of Static Fields in Static Class
Solution 1:
Yes, they will, please see clause 15.5.6.2 of the C# specification:
The static field variable initializers of a class correspond to a sequence of assignments that are executed in the textual order in which they appear in the class declaration (§15.5.6.1). Within a partial class, the meaning of "textual order" is specified by §15.5.6.1. If a static constructor (§15.12) exists in the class, execution of the static field initializers occurs immediately prior to executing that static constructor. Otherwise, the static field initializers are executed at an implementation-dependent time prior to the first use of a static field of that class.
That being said I think it would be better to do the initialization inside a static type initializer (static constructor).
Solution 2:
Hmm... I'm surprised that compiles (it does, I checked). I'm not aware of any guarantee that would make this safe. Use a static constructor...
Edit: I accept (see better answer above) that it will work; but my idea with code is to keep it as simple and obvious as possible. If it isn't obvious that it will work (and it can't be if you have to ask), then don't write it that way...
In particular, problems with relying on field order:
- it can break if you move code around (which I often do)
- it can break if you split the code into
partial
classes
My advice remains: use a static constructor for this scenario.