Android - Check whether a value exist in an Array

I have an array named "bob" which contains values.

String[] bob = { "this", "is", "a", "really", "silly", "list" };

How can I know whether "silly" value exists in the array named bob without iterating through it?

You can use List#contains method. For that you need to convert your array to a list. You can use Arrays#asList() method fot that:

String[] bob = { "this", "is", "a", "really", "silly", "list" };

if (Arrays.asList(bob).contains("silly")) {
    // true
}

Convert the Array to List using static Arrays.asList(T) and check with List.contains(Object) to check if an object exists in the retuned collection.

    String[] bob = { "this", "is", "a", "really", "silly", "list" };
           System.out.println(Arrays.asList(bob).contains("silly"));

Traditional way however would be to iterate over the array and check at each element using equals().

If you are going to check it a lot you may find it more efficient to use a HashSet:

String[] bob = { "this", "is", "a", "really", "silly", "list" };
Set<String> silly = new HashSet<String>(Arrays.asList(bob));
boolean isSilly = silly.contains("silly");

Here is an easy way to do it:

    ArrayList list = new ArrayList(Arrays.asList(bob ));
    if (list.contains("silly")) {
                    // my array has silly !
             }

The idea is to convert your Array to a ListArray object. but it would consume extra memory, so make sure it is worth it before using it.

Edit

If you are after peformance and saving memory you can use binary search algorthem instead: this way you don't have to allocate new objects:

Arrays.sort(array) 
int value = Arrays.binarySearch(array, "silly");
if (value != -1) {
// my array has silly !
}