Check if User Inputs a Letter or Number in C

Solution 1:

It's best to test for decimal numeric digits themselves instead of letters. isdigit.

#include <ctype.h>

if(isdigit(variable))
{
  //valid input
}
else
{
  //invalid input
}

Solution 2:

#include <ctype.h>
if (isalpha(variable)) { ... }

Solution 3:

isalpha() will test one character at a time. If the user input a number like 23A4, then you want to test every letter. You can use this:

bool isNumber(char *input) {
    for (i = 0; input[i] != '\0'; i++)
        if (isalpha(input[i]))
            return false;
    return true;
}

// accept and check
scanf("%s", input);  // where input is a pointer to a char with memory allocated
if (isNumber(input)) {
    number = atoi(input);
    // rest of the code
}

I agree that atoi() is not thread safe and a deprecated function. You can write another simple function in place of that.

Solution 4:

Aside from the isalpha function, you can do it like this:

char vrbl;

if ((vrbl >= 'a' && vrbl <= 'z') || (vrbl >= 'A' && vrbl <= 'Z')) 
{
    printf("You entered a letter! You must enter a number!");
}

Solution 5:

The strto*() library functions come in handy here:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#define SIZE ...

int main(void)
{
  char buffer[SIZE];
  printf("Gimme an integer value: ");
  fflush(stdout);
  if (fgets(buffer, sizeof buffer, stdin))
  {
    long value;
    char *check;
    /**
     * strtol() scans the string and converts it to the equivalent 
     * integer value.  check will point to the first character
     * in the buffer that isn't part of a valid integer constant;
     * e.g., if you type in "12W", check will point to 'W'.  
     *
     * If check points to something other than whitespace or a 0
     * terminator, then the input string is not a valid integer. 
     */
    value = strtol(buffer, &check, 0);
    if (!isspace(*check) && *check != 0)
    {
      printf("%s is not a valid integer\n", buffer);
    }
  }
  return 0;
}