How to repeat a char using printf?

You can use the following technique:

printf("%.*s", 5, "=================");

This will print "=====" It works for me on Visual Studio, no reason it shouldn't work on all C compilers.

Short answer - yes, long answer: not how you want it.

You can use the %* form of printf, which accepts a variable width. And, if you use '0' as your value to print, combined with the right-aligned text that's zero padded on the left..

printf("%0*d\n", 20, 0);

produces:

00000000000000000000

With my tongue firmly planted in my cheek, I offer up this little horror-show snippet of code.

Some times you just gotta do things badly to remember why you try so hard the rest of the time.

#include <stdio.h>

int width = 20;
char buf[4096];

void subst(char *s, char from, char to) {
    while (*s == from)
    *s++ = to;
}

int main() {
    sprintf(buf, "%0*d", width, 0);
    subst(buf, '0', '-');
    printf("%s\n", buf);
    return 0;
}

If you limit yourself to repeating either a 0 or a space you can do:

For spaces:

printf("%*s", count, "");

For zeros:

printf("%0*d", count, 0);

How to repeat a char using printf?

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