Split string and take last element

I have a table with this values:

Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx
OurStory/MeettheFoodieandtheMD.aspx
TheFood/OurMenu.aspx

I want to get this

Diet.aspx
MeettheFoodieandtheMD.aspx
OurMenu.aspx

How can i do this?

Solution 1:

The way to do it in SQL :

SELECT SUBSTRING( string , LEN(string) -  CHARINDEX('/',REVERSE(string)) + 2  , LEN(string)  ) FROM SAMPLE;

JSFiddle here http://sqlfiddle.com/#!3/41ead/11

Solution 2:

SELECT REVERSE(LEFT(REVERSE(columnName), CHARINDEX('/', REVERSE(columnName)) - 1))
FROM   tableName

SQLFiddle Demo

ORHER SOURCE(s)

REVERSE
LEFT
CHARINDEX

Solution 3:

Please try:

select url,(CASE WHEN CHARINDEX('/', url, 1)=0 THEN url ELSE RIGHT(url, CHARINDEX('/', REVERSE(url)) - 1) END)
from(
    select 'Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx' as url union
    select 'OurStory/MeettheFoodieandtheMD.aspx' as url union
    select 'MeettheFoodieandtheMD.aspx' as url
)xx

Solution 4:

SELECT REVERSE ((
    SELECT TOP 1 value FROM STRING_SPLIT(REVERSE('Articles/Search/ArtMID/2681/ArticleID/2218/Diet.aspx'), '/')
)) AS fName
Result: Diet.aspx

Standard STRING_SPLIT does not allow to take last value.

The trick is to reverse the string (REVERSE) before splitting with STRING_SPLIT, get the first value from the end (TOP 1 value) and then the result needs to be reversed again (REVERSE) to restore the original chars sequence.

Here is the common approach, when working with SQL table:

SELECT REVERSE ((
    SELECT TOP 1 VALUE FROM STRING_SPLIT(REVERSE(mySearchString), '/')
)) AS myLastValue
FROM myTable

Solution 5:

Try this. It's easier.

SELECT RIGHT(string, CHARINDEX('/', REVERSE(string)) -1) FROM TableName