Python urlparse -- extract domain name without subdomain

Need a way to extract a domain name without the subdomain from a url using Python urlparse.

For example, I would like to extract "google.com" from a full url like "http://www.google.com".

The closest I can seem to come with urlparse is the netloc attribute, but that includes the subdomain, which in this example would be www.google.com.

I know that it is possible to write some custom string manipulation to turn www.google.com into google.com, but I want to avoid by-hand string transforms or regex in this task. (The reason for this is that I am not familiar enough with url formation rules to feel confident that I could consider every edge case required in writing a custom parsing function.)

Or, if urlparse can't do what I need, does anyone know any other Python url-parsing libraries that would?

You probably want to check out tldextract, a library designed to do this kind of thing.

It uses the Public Suffix List to try and get a decent split based on known gTLDs, but do note that this is just a brute-force list, nothing special, so it can get out of date (although hopefully it's curated so as not to).

>>> import tldextract
>>> tldextract.extract('http://forums.news.cnn.com/')
ExtractResult(subdomain='forums.news', domain='cnn', suffix='com')

So in your case:

>>> extracted = tldextract.extract('http://www.google.com')
>>> "{}.{}".format(extracted.domain, extracted.suffix)
"google.com"

This is an update, based on the bounty request for an updated answer

Start by using the tld package. A description of the package:

Extracts the top level domain (TLD) from the URL given. List of TLD names is taken from Mozilla http://mxr.mozilla.org/mozilla/source/netwerk/dns/src/effective_tld_names.dat?raw=1

from tld import get_tld
from tld.utils import update_tld_names
update_tld_names()

print get_tld("http://www.google.co.uk")
print get_tld("http://zap.co.it")
print get_tld("http://google.com")
print get_tld("http://mail.google.com")
print get_tld("http://mail.google.co.uk")
print get_tld("http://google.co.uk")

This outputs

google.co.uk
zap.co.it
google.com
google.com
google.co.uk
google.co.uk

Notice that it correctly handles country level TLDs by leaving co.uk and co.it, but properly removes the www and mail subdomains for both .com and .co.uk

The update_tld_names() call at the beginning of the script is used to update/sync the tld names with the most recent version from Mozilla.

This is not a standard decomposition of the URLs.

You cannot rely on the www. to be present or optional. In a lot of cases it will not.

So if you do want to assume that only the last two components are relevant (which also won't work for the uk, e.g. www.google.co.uk) then you can do a split('.')[-2:].

Or, which is actually less error prone, strip a www. prefix.

But in either way you cannot assume that the www. is optional, because it will NOT work every time!

Here is a list of common suffixes for domains. You can try to keep the suffix + one component.

https://mxr.mozilla.org/mozilla-central/source/netwerk/dns/effective_tld_names.dat?raw=1

But how do you plan to handle for example first.last.name domains? Assume that all the users with the same last name are the same company? Initially, you would only be able to get third-level domains there. By now, you apparently can get second level, too. So for .name there is no general rule.

For domain name manipulation, you can also use Dnspy (Disclaimer: I wrote this library)

It helps extract domains (and domain labels) at various levels, using a fresh copy of Mozilla Public Suffix list.