How do I write a function that returns another function?

Solution 1:

Try this, using Python:

import math
def make_cylinder_volume_func(r):
    def volume(h):
        return math.pi * r * r * h
    return volume

Use it like this, for example with radius=10 and height=5:

volume_radius_10 = make_cylinder_volume_func(10)
volume_radius_10(5)
=> 1570.7963267948967

Notice that returning a function was a simple matter of defining a new function inside the function, and returning it at the end - being careful to pass the appropriate parameters for each function. FYI, the technique of returning a function from another function is known as currying.

Solution 2:

Using lambdas, also known as anonymous functions, you can abstract out the volume function inside the make_cylinder_volume_func to a single line. In no way different from Óscar López's answer, the solution using lambda is still in a sense 'more functional'.

This is how you can write the accepted answer using a lambda expression:

import math
def make_cylinder_volume_fun(r):
    return lambda h: math.pi * r * r * h

And then call as you'd any other curried function:

volume_radius_1 = make_cylinder_volume_fun(1)
volume_radius_1(1) 
=> 3.141592653589793

Solution 3:

Just want to point out that you can do this with pymonad

 import pymonad 

 @pymonad.curry
 def add(a, b):
     return a + b

 add5 = add(5)
 add5(4)
 9

Solution 4:

I know I am too late to the party, but I think you might find this solution interesting.

from math import pi
from functools import partial

def cylinder_volume(r, h):
    return pi * r * r * h

make_cylinder_with_radius_2 = partial(cylinder_volume, 2)
make_cylinder_with_height_3 = partial(cylinder_volume, h=3)

print(cylinder_volume(2, 3))            # 37.6991118431
print(make_cylinder_with_radius_2(3))   # 37.6991118431
print(make_cylinder_with_height_3(2))   # 37.6991118431

Here is documentation about how partial works.