Java Executors: how can I stop submitted tasks?
I have submitted a task using executors and I need it to stop after some time (e.g. 5 minutes). I have tried doing like this:
for (Future<?> fut : e.invokeAll(tasks, 300, TimeUnit.SECONDS)) {
try {
fut.get();
} catch (CancellationException ex) {
fut.cancel(true);
tasks.clear();
} catch(ExecutionException ex){
ex.printStackTrace(); //FIXME: gestita con printstack
}
}
But I always get an error: I have a shared Vector that needs to be modified by the tasks and then read by a thread, and even if I stop all the task, if the timeout occurs I get:
Exception in thread "Thread-1" java.util.ConcurrentModificationException
Is there something wrong? How can I stop the tasks submitted that are still working after 5 minutes?
Just because you call cancel()
on Future
doesn't mean that the task will stop automatically. You have to do some work within the task to make sure that it will stop:
- Use
cancel(true)
so that an interrupt is sent to the task. - Handle
InterruptedException
. If a function in your task throws anInterruptedException
, make sure you exit gracefully as soon as possible upon catching the exception. - Periodically check
Thread.currentThread().isInterrupted()
if the task does continuous computation.
For example:
class LongTask implements Callable<Double> {
public Double call() {
// Sleep for a while; handle InterruptedException appropriately
try {
Thread.sleep(10000);
} catch (InterruptedException ex) {
System.out.println("Exiting gracefully!");
return null;
}
// Compute for a while; check Thread.isInterrupted() periodically
double sum = 0.0;
for (long i = 0; i < 10000000; i++) {
sum += 10.0
if (Thread.currentThread().isInterrupted()) {
System.out.println("Exiting gracefully");
return null;
}
}
return sum;
}
}
Also, as other posts have mentioned: ConcurrentModificationException
can be thrown even if using the thread-safe Vector
class, because iterators you obtain from Vector
are not thread-safe, and thus need to be synchronized. The enhanced for-loop uses iterators, so watch out:
final Vector<Double> vector = new Vector<Double>();
vector.add(1.0);
vector.add(2.0);
// Not thread safe! If another thread modifies "vector" during the loop, then
// a ConcurrentModificationException will be thrown.
for (Double num : vector) {
System.out.println(num);
}
// You can try this as a quick fix, but it might not be what you want:
synchronized (vector) { // "vector" must be final
for (Double num : vector) {
System.out.println(num);
}
}
The ConcurrentModificationException
is coming from your call to tasks.clear()
while your Exceutors is iterating over your tasks
Vector
. What you can try to do is call shutdownNow()
on your ExecutorService