Calculate Difference between two times in Android
Solution 1:
Try below code.
// suppose time format is into ("hh:mm a") format
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("hh:mm a");
date1 = simpleDateFormat.parse("08:00 AM");
date2 = simpleDateFormat.parse("04:00 PM");
long difference = date2.getTime() - date1.getTime();
days = (int) (difference / (1000*60*60*24));
hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
hours = (hours < 0 ? -hours : hours);
Log.i("======= Hours"," :: "+hours);
Output - Hours :: 8
Solution 2:
Note: Corrected code as below which provide by Chirag Raval because in code which Chirag provided had some issues when we try to find time from 22:00 to 07:00.
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm");
Date startDate = simpleDateFormat.parse("22:00");
Date endDate = simpleDateFormat.parse("07:00");
long difference = endDate.getTime() - startDate.getTime();
if(difference<0)
{
Date dateMax = simpleDateFormat.parse("24:00");
Date dateMin = simpleDateFormat.parse("00:00");
difference=(dateMax.getTime() -startDate.getTime() )+(endDate.getTime()-dateMin.getTime());
}
int days = (int) (difference / (1000*60*60*24));
int hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
int min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
Log.i("log_tag","Hours: "+hours+", Mins: "+min);
Result will be: Hours: 9, Mins: 0