How to check if a python module exists without importing it
I need to know if a python module exists, without importing it.
Importing something that might not exist (not what I want):
try:
import eggs
except ImportError:
pass
Solution 1:
Python2
To check if import can find something in python2, using imp
import imp
try:
imp.find_module('eggs')
found = True
except ImportError:
found = False
To find dotted imports, you need to do more:
import imp
try:
spam_info = imp.find_module('spam')
spam = imp.load_module('spam', *spam_info)
imp.find_module('eggs', spam.__path__) # __path__ is already a list
found = True
except ImportError:
found = False
You can also use pkgutil.find_loader
(more or less the same as the python3 part
import pkgutil
eggs_loader = pkgutil.find_loader('eggs')
found = eggs_loader is not None
Python3
Python3 ≤ 3.3
You should use importlib
, How I went about doing this was:
import importlib
spam_loader = importlib.find_loader('spam')
found = spam_loader is not None
My expectation being, if you can find a loader for it, then it exists. You can also be a bit more smart about it, like filtering out what loaders you will accept. For example:
import importlib
spam_loader = importlib.find_loader('spam')
# only accept it as valid if there is a source file for the module - no bytecode only.
found = issubclass(type(spam_loader), importlib.machinery.SourceFileLoader)
Python3 ≥ 3.4
In Python3.4 importlib.find_loader
python docs was deprecated in favour of importlib.util.find_spec
. The recommended method is the importlib.util.find_spec
. There are others like importlib.machinery.FileFinder
, which is useful if you're after a specific file to load. Figuring out how to use them is beyond the scope of this.
import importlib
spam_spec = importlib.util.find_spec("spam")
found = spam_spec is not None
This also works with relative imports but you must supply the starting package, so you could also do:
import importlib
spam_spec = importlib.util.find_spec("..spam", package="eggs.bar")
found = spam_spec is not None
spam_spec.name == "eggs.spam"
While I'm sure there exists a reason for doing this - I'm not sure what it would be.
WARNING
When trying to find a submodule, it will import the parent module (for all of the above methods)!
food/
|- __init__.py
|- eggs.py
## __init__.py
print("module food loaded")
## eggs.py
print("module eggs")
were you then to run
>>> import importlib
>>> spam_spec = importlib.find_spec("food.eggs")
module food loaded
ModuleSpec(name='food.eggs', loader=<_frozen_importlib.SourceFileLoader object at 0x10221df28>, origin='/home/user/food/eggs.py')
comments welcome on getting around this
Acknowledgements
- @rvighne for importlib
- @lucas-guido for python3.3+ depricating
find_loader
- @enpenax for pkgutils.find_loader behaviour in python2.7
Solution 2:
Python 3 >= 3.6: ModuleNotFoundError
The ModuleNotFoundError
has been introduced in python 3.6 and can be used for this purpose
try:
import eggs
except ModuleNotFoundError:
# Error handling
pass
The error is raised when a module or one of its parents cannot be found. So
try:
import eggs.sub
except ModuleNotFoundError as err:
# Error handling
print(err)
would print a message that looks like No module named 'eggs'
if the eggs
module cannot be found; but would print something like No module named 'eggs.sub'
if only the sub
module couldn't be found but the eggs
package could be found.
See the documentation of the import system for more info on the ModuleNotFoundError