Size of Matrix OpenCV
I know this might be very rudimentary, but I am new to OpenCV. Could you please tell me how to obtain the size of a matrix in OpenCV?. I googled and I am still searching, but if any of you know the answer, please help me.
Size as in number of rows and columns.
And is there a way to directly obtain the maximum value of a 2D matrix?
cv:Mat mat;
int rows = mat.rows;
int cols = mat.cols;
cv::Size s = mat.size();
rows = s.height;
cols = s.width;
Note that apart from rows and columns there is a number of channels and type. When it is clear what type is, the channels can act as an extra dimension as in CV_8UC3 so you would address a matrix as
uchar a = M.at<Vec3b>(y, x)[i];
So the size in terms of elements of elementary type is M.rows * M.cols * M.cn
To find the max element one can use
Mat src;
double minVal, maxVal;
minMaxLoc(src, &minVal, &maxVal);
For 2D matrix:
mat.rows – Number of rows in a 2D array.
mat.cols – Number of columns in a 2D array.
Or: C++: Size Mat::size() const
The method returns a matrix size: Size(cols, rows) . When the matrix is more than 2-dimensional, the returned size is (-1, -1).
For multidimensional matrix, you need to use
int thisSizes[3] = {2, 3, 4};
cv::Mat mat3D(3, thisSizes, CV_32FC1);
// mat3D.size tells the size of the matrix
// mat3D.size[0] = 2;
// mat3D.size[1] = 3;
// mat3D.size[2] = 4;
Note, here 2 for z axis, 3 for y axis, 4 for x axis. By x, y, z, it means the order of the dimensions. x index changes the fastest.
If you are using the Python wrappers, then (assuming your matrix name is mat):
mat.shape gives you an array of the type- [height, width, channels]
mat.size gives you the size of the array
Sample Code:
import cv2
mat = cv2.imread('sample.png')
height, width, channel = mat.shape[:3]
size = mat.size