JQuery .each() backwards

$($("li").get().reverse()).each(function() { /* ... */ });

I present you with the cleanest way ever, in the form of the world's smallest jquery plugin:

jQuery.fn.reverse = [].reverse;

Usage:

$('jquery-selectors-go-here').reverse().each(function () {
    //business as usual goes here
});

-All credit to Michael Geary in his post here: http://www.mail-archive.com/[email protected]/msg04261.html

You can do

jQuery.fn.reverse = function() {
    return this.pushStack(this.get().reverse(), arguments);
}; 

followed by

$(selector).reverse().each(...) 

Here are different options for this:

First: without jQuery:

var lis = document.querySelectorAll('ul > li');
var contents = [].map.call(lis, function (li) {
    return li.innerHTML;
}).reverse().forEach(function (content, i) {
    lis[i].innerHTML = content;
});

Demo here

... and with jQuery:

You can use this:

$($("ul > li").get().reverse()).each(function (i) {
    $(this).text( 'Item ' + (++i));
});

Demo here

Another way, using also jQuery with reverse is:

$.fn.reverse = [].reverse;
$("ul > li").reverse().each(function (i) {
    $(this).text( 'Item ' + (++i));
});

This demo here.

One more alternative is to use the length (count of elements matching that selector) and go down from there using the index of each iteration. Then you can use this:

var $li = $("ul > li");
$li.each(function (i) {
    $(this).text( 'Item ' + ($li.length - i));
});

This demo here

One more, kind of related to the one above:

var $li = $("ul > li");
$li.text(function (i) {
    return 'Item ' + ($li.length - i);
});

Demo here