How to read the RGB value of a given pixel in Python?
If I open an image with open("image.jpg")
, how can I get the RGB values of a pixel assuming I have the coordinates of the pixel?
Then, how can I do the reverse of this? Starting with a blank graphic, 'write' a pixel with a certain RGB value?
I would prefer if I didn't have to download any additional libraries.
Solution 1:
It's probably best to use the Python Image Library to do this which I'm afraid is a separate download.
The easiest way to do what you want is via the load() method on the Image object which returns a pixel access object which you can manipulate like an array:
from PIL import Image
im = Image.open('dead_parrot.jpg') # Can be many different formats.
pix = im.load()
print im.size # Get the width and hight of the image for iterating over
print pix[x,y] # Get the RGBA Value of the a pixel of an image
pix[x,y] = value # Set the RGBA Value of the image (tuple)
im.save('alive_parrot.png') # Save the modified pixels as .png
Alternatively, look at ImageDraw which gives a much richer API for creating images.
Solution 2:
Using Pillow (which works with Python 3.X as well as Python 2.7+), you can do the following:
from PIL import Image
im = Image.open('image.jpg', 'r')
width, height = im.size
pixel_values = list(im.getdata())
Now you have all pixel values. If it is RGB or another mode can be read by im.mode
. Then you can get pixel (x, y)
by:
pixel_values[width*y+x]
Alternatively, you can use Numpy and reshape the array:
>>> pixel_values = numpy.array(pixel_values).reshape((width, height, 3))
>>> x, y = 0, 1
>>> pixel_values[x][y]
[ 18 18 12]
A complete, simple to use solution is
# Third party modules
import numpy
from PIL import Image
def get_image(image_path):
"""Get a numpy array of an image so that one can access values[x][y]."""
image = Image.open(image_path, "r")
width, height = image.size
pixel_values = list(image.getdata())
if image.mode == "RGB":
channels = 3
elif image.mode == "L":
channels = 1
else:
print("Unknown mode: %s" % image.mode)
return None
pixel_values = numpy.array(pixel_values).reshape((width, height, channels))
return pixel_values
image = get_image("gradient.png")
print(image[0])
print(image.shape)
Smoke testing the code
You might be uncertain about the order of width / height / channel. For this reason I've created this gradient:
The image has a width of 100px and a height of 26px. It has a color gradient going from #ffaa00
(yellow) to #ffffff
(white). The output is:
[[255 172 5]
[255 172 5]
[255 172 5]
[255 171 5]
[255 172 5]
[255 172 5]
[255 171 5]
[255 171 5]
[255 171 5]
[255 172 5]
[255 172 5]
[255 171 5]
[255 171 5]
[255 172 5]
[255 172 5]
[255 172 5]
[255 171 5]
[255 172 5]
[255 172 5]
[255 171 5]
[255 171 5]
[255 172 4]
[255 172 5]
[255 171 5]
[255 171 5]
[255 172 5]]
(100, 26, 3)
Things to note:
- The shape is (width, height, channels)
- The
image[0]
, hence the first row, has 26 triples of the same color
Solution 3:
PyPNG - lightweight PNG decoder/encoder
Although the question hints at JPG, I hope my answer will be useful to some people.
Here's how to read and write PNG pixels using PyPNG module:
import png, array
point = (2, 10) # coordinates of pixel to be painted red
reader = png.Reader(filename='image.png')
w, h, pixels, metadata = reader.read_flat()
pixel_byte_width = 4 if metadata['alpha'] else 3
pixel_position = point[0] + point[1] * w
new_pixel_value = (255, 0, 0, 0) if metadata['alpha'] else (255, 0, 0)
pixels[
pixel_position * pixel_byte_width :
(pixel_position + 1) * pixel_byte_width] = array.array('B', new_pixel_value)
output = open('image-with-red-dot.png', 'wb')
writer = png.Writer(w, h, **metadata)
writer.write_array(output, pixels)
output.close()
PyPNG is a single pure Python module less than 4000 lines long, including tests and comments.
PIL is a more comprehensive imaging library, but it's also significantly heavier.
Solution 4:
As Dave Webb said:
Here is my working code snippet printing the pixel colours from an image:
import os, sys import Image im = Image.open("image.jpg") x = 3 y = 4 pix = im.load() print pix[x,y]