How to avoid memory leaks when using a vector of pointers to dynamically allocated objects in C++?
I'm using a vector of pointers to objects. These objects are derived from a base class, and are being dynamically allocated and stored.
For example, I have something like:
vector<Enemy*> Enemies;
and I'll be deriving from the Enemy class and then dynamically allocating memory for the derived class, like this:
enemies.push_back(new Monster());
What are things I need to be aware of to avoid memory leaks and other problems?
std::vector will manage the memory for you, like always, but this memory will be of pointers, not objects.
What this means is that your classes will be lost in memory once your vector goes out of scope. For example:
#include <vector>
struct base
{
virtual ~base() {}
};
struct derived : base {};
typedef std::vector<base*> container;
void foo()
{
container c;
for (unsigned i = 0; i < 100; ++i)
c.push_back(new derived());
} // leaks here! frees the pointers, doesn't delete them (nor should it)
int main()
{
foo();
}
What you'd need to do is make sure you delete all the objects before the vector goes out of scope:
#include <algorithm>
#include <vector>
struct base
{
virtual ~base() {}
};
struct derived : base {};
typedef std::vector<base*> container;
template <typename T>
void delete_pointed_to(T* const ptr)
{
delete ptr;
}
void foo()
{
container c;
for (unsigned i = 0; i < 100; ++i)
c.push_back(new derived());
// free memory
std::for_each(c.begin(), c.end(), delete_pointed_to<base>);
}
int main()
{
foo();
}
This is difficult to maintain, though, because we have to remember to perform some action. More importantly, if an exception were to occur in-between the allocation of elements and the deallocation loop, the deallocation loop would never run and you're stuck with the memory leak anyway! This is called exception safety and it's a critical reason why deallocation needs to be done automatically.
Better would be if the pointers deleted themselves. Theses are called smart pointers, and the standard library provides std::unique_ptr and std::shared_ptr.
std::unique_ptr represents a unique (unshared, single-owner) pointer to some resource. This should be your default smart pointer, and overall complete replacement of any raw pointer use.
auto myresource = /*std::*/make_unique<derived>(); // won't leak, frees itself
std::make_unique is missing from the C++11 standard by oversight, but you can make one yourself. To directly create a unique_ptr (not recommended over make_unique if you can), do this:
std::unique_ptr<derived> myresource(new derived());
Unique pointers have move semantics only; they cannot be copied:
auto x = myresource; // error, cannot copy
auto y = std::move(myresource); // okay, now myresource is empty
And this is all we need to use it in a container:
#include <memory>
#include <vector>
struct base
{
virtual ~base() {}
};
struct derived : base {};
typedef std::vector<std::unique_ptr<base>> container;
void foo()
{
container c;
for (unsigned i = 0; i < 100; ++i)
c.push_back(make_unique<derived>());
} // all automatically freed here
int main()
{
foo();
}
shared_ptr has reference-counting copy semantics; it allows multiple owners sharing the object. It tracks how many shared_ptrs exist for an object, and when the last one ceases to exist (that count goes to zero), it frees the pointer. Copying simply increases the reference count (and moving transfers ownership at a lower, almost free cost). You make them with std::make_shared (or directly as shown above, but because shared_ptr has to internally make allocations, it's generally more efficient and technically more exception-safe to use make_shared).
#include <memory>
#include <vector>
struct base
{
virtual ~base() {}
};
struct derived : base {};
typedef std::vector<std::shared_ptr<base>> container;
void foo()
{
container c;
for (unsigned i = 0; i < 100; ++i)
c.push_back(std::make_shared<derived>());
} // all automatically freed here
int main()
{
foo();
}
Remember, you generally want to use std::unique_ptr as a default because it's more lightweight. Additionally, std::shared_ptr can be constructed out of a std::unique_ptr (but not vice versa), so it's okay to start small.
Alternatively, you could use a container created to store pointers to objects, such as a boost::ptr_container:
#include <boost/ptr_container/ptr_vector.hpp>
struct base
{
virtual ~base() {}
};
struct derived : base {};
// hold pointers, specially
typedef boost::ptr_vector<base> container;
void foo()
{
container c;
for (int i = 0; i < 100; ++i)
c.push_back(new Derived());
} // all automatically freed here
int main()
{
foo();
}
While boost::ptr_vector<T> had obvious use in C++03, I can't speak of the relevance now because we can use std::vector<std::unique_ptr<T>> with probably little to no comparable overhead, but this claim should be tested.
Regardless, never explicitly free things in your code. Wrap things up to make sure resource management is dealt with automatically. You should have no raw owning pointers in your code.
As a default in a game, I would probably go with std::vector<std::shared_ptr<T>>. We expect sharing anyway, it's fast enough until profiling says otherwise, it's safe, and it's easy to use.
The trouble with using vector<T*> is that, whenever the vector goes out of scope unexpectedly (like when an exception is thrown), the vector cleans up after yourself, but this will only free the memory it manages for holding the pointer, not the memory you allocated for what the pointers are referring to. So GMan's delete_pointed_to function is of limited value, as it only works when nothing goes wrong.
What you need to do is to use a smart pointer:
vector< std::tr1::shared_ptr<Enemy> > Enemies;
(If your std lib comes without TR1, use boost::shared_ptr instead.)
Except for very rare corner cases (circular references) this simply removes the trouble of object lifetime.
Edit: Note that GMan, in his detailed answer, mentions this, too.
I am assuming following:
- You are having a vector like vector< base* >
- You are pushing the pointers to this vector after allocating the objects on heap
- You want to do a push_back of derived* pointer into this vector.
Following things come to my mind:
- Vector will not release the memory of the object pointed to by the pointer. You have to delete it itself.
- Nothing specific to vector, but the base class destructor should be virtual.
- vector< base* > and vector< derived* > are two totally different types.