how to get process file name from PID in MacOS?
Is it possible to get a file name of a process using PID? ps displays a lot of useful information about a process, but not a hint about a process executable file location.
Solution 1:
One way of getting the process's binary location is to use lsof
and grep
for the first txt
segment. For example, in the shell to see what binary the shell is, use the shell's PID in place of $$
.
$ lsof -p $$ | grep txt
bash 78228 blair txt REG 14,2 1244928 6568359 /bin/bash
bash 78228 blair txt REG 14,2 1059792 23699809 /usr/lib/dyld
bash 78228 blair txt REG 14,2 136368128 81751398 /private/var/db/dyld/dyld_shared_cache_i386
You can see that the shell is using /bin/bash
.
This technique works if the process was launched using an absolute or relative path. For example, going into one shell and running
$ sleep 1234567
and using ps
in another shell only shows how it was launched:
$ ps auxww|grep '[s]leep'
blair 79462 0.0 0.0 600908 744 s011 S+ 11:17PM 0:00.00 sleep 1234567
using lsof
shows which binary it ran:
$ lsof -p 79462 | awk '$4 == "txt" { print $9 }'
/opt/local-development/bin/gsleep
I have MacPorts coreutils +with_default_names installed, which explains that I picked up gsleep
and not /bin/sleep
.
Solution 2:
ps -ef with grep works for me. For a specific file name, simply pipe through grep thus:
MacBook:~ Me$ ps -ef | grep Safari | grep -v grep
501 15733 301 0 0:25.76 ?? 1:58.24 /Applications/Safari.app/Contents/MacOS/Safari -psn_0_4977855
(That final 'grep -v grep' simply stops you getting your own grep command in the output)