Calculate the number of months between two dates in PHP?

$date1 = '2000-01-25';
$date2 = '2010-02-20';

$ts1 = strtotime($date1);
$ts2 = strtotime($date2);

$year1 = date('Y', $ts1);
$year2 = date('Y', $ts2);

$month1 = date('m', $ts1);
$month2 = date('m', $ts2);

$diff = (($year2 - $year1) * 12) + ($month2 - $month1);

You may want to include the days somewhere too, depending on whether you mean whole months or not. Hope you get the idea though.

This is a simple method I wrote in my class to count the number of months involved into two given dates :

public function nb_mois($date1, $date2)
{
    $begin = new DateTime( $date1 );
    $end = new DateTime( $date2 );
    $end = $end->modify( '+1 month' );

    $interval = DateInterval::createFromDateString('1 month');

    $period = new DatePeriod($begin, $interval, $end);
    $counter = 0;
    foreach($period as $dt) {
        $counter++;
    }

    return $counter;
}

Here is my solution. It checks both years and months of dates and find difference.

 $date1 = '2000-01-25';
 $date2 = '2010-02-20';
 $d1=new DateTime($date2); 
 $d2=new DateTime($date1);                                  
 $Months = $d2->diff($d1); 
 $howeverManyMonths = (($Months->y) * 12) + ($Months->m);

Like this:

$date1 = strtotime('2000-01-25');
$date2 = strtotime('2010-02-20');
$months = 0;

while (($date1 = strtotime('+1 MONTH', $date1)) <= $date2)
    $months++;

echo $months;

If you want to include days to, then use this:

$date1 = strtotime('2000-01-25');
$date2 = strtotime('2010-02-20');

$months = 0;

while (strtotime('+1 MONTH', $date1) < $date2) {
    $months++;
    $date1 = strtotime('+1 MONTH', $date1);
}

echo $months, ' month, ', ($date2 - $date1) / (60*60*24), ' days'; // 120 month, 26 days