SQL query for a carriage return in a string and ultimately removing carriage return

Solution 1:

this will be slow, but if it is a one time thing, try...

select * from parameters where name like '%'+char(13)+'%' or name like '%'+char(10)+'%'

Note that the ANSI SQL string concatenation operator is "||", so it may need to be:

select * from parameters where name like '%' || char(13) || '%' or name like '%' || char(10) || '%'

The main question was to remove the CR/LF. Using the replace and char functions works for me:

Select replace(replace(Name,char(10),''),char(13),'')

For Postgres or Oracle SQL, use the CHR function instead:

       replace(replace(Name,CHR(10),''),CHR(13),'')

In SQL Server I would use:

WHERE CHARINDEX(CHAR(13), name) <> 0 OR CHARINDEX(CHAR(10), name) <> 0

This will search for both carriage returns and line feeds.

If you want to search for tabs too just add:

OR CHARINDEX(CHAR(9), name) <> 0

You can also use regular expressions:

SELECT * FROM Parameters WHERE Name REGEXP '\n';