C++ Compare char array with string
Solution 1:
Use strcmp()
to compare the contents of strings:
if (strcmp(var1, "dev") == 0) {
}
Explanation: in C, a string is a pointer to a memory location which contains bytes. Comparing a char*
to a char*
using the equality operator won't work as expected, because you are comparing the memory locations of the strings rather than their byte contents. A function such as strcmp()
will iterate through both strings, checking their bytes to see if they are equal. strcmp()
will return 0 if they are equal, and a non-zero value if they differ. For more details, see the manpage.
Solution 2:
You're not working with strings. You're working with pointers.
var1
is a char pointer (const char*
). It is not a string. If it is null-terminated, then certain C functions will treat it as a string, but it is fundamentally just a pointer.
So when you compare it to a char array, the array decays to a pointer as well, and the compiler then tries to find an operator == (const char*, const char*)
.
Such an operator does exist. It takes two pointers and returns true
if they point to the same address. So the compiler invokes that, and your code breaks.
IF you want to do string comparisons, you have to tell the compiler that you want to deal with strings, not pointers.
The C way of doing this is to use the strcmp
function:
strcmp(var1, "dev");
This will return zero if the two strings are equal. (It will return a value greater than zero if the left-hand side is lexicographically greater than the right hand side, and a value less than zero otherwise.)
So to compare for equality you need to do one of these:
if (!strcmp(var1, "dev")){...}
if (strcmp(var1, "dev") == 0) {...}
However, C++ has a very useful string
class. If we use that your code becomes a fair bit simpler. Of course we could create strings from both arguments, but we only need to do it with one of them:
std::string var1 = getenv("myEnvVar");
if(var1 == "dev")
{
// do stuff
}
Now the compiler encounters a comparison between string and char pointer. It can handle that, because a char pointer can be implicitly converted to a string, yielding a string/string comparison. And those behave exactly as you'd expect.