Check whether variable is number or string in JavaScript
Solution 1:
If you're dealing with literal notation, and not constructors, you can use typeof:.
typeof "Hello World"; // string
typeof 123; // number
If you're creating numbers and strings via a constructor, such as var foo = new String("foo")
, you should keep in mind that typeof
may return object
for foo
.
Perhaps a more foolproof method of checking the type would be to utilize the method found in underscore.js (annotated source can be found here),
var toString = Object.prototype.toString;
_.isString = function (obj) {
return toString.call(obj) == '[object String]';
}
This returns a boolean true
for the following:
_.isString("Jonathan"); // true
_.isString(new String("Jonathan")); // true
Solution 2:
Best way to do that is using isNaN
+ type casting:
Updated all-in method:
function isNumber(n) { return !isNaN(parseFloat(n)) && !isNaN(n - 0) }
The same using regex:
function isNumber(n) { return /^-?[\d.]+(?:e-?\d+)?$/.test(n); }
------------------------
isNumber('123'); // true
isNumber('123abc'); // false
isNumber(5); // true
isNumber('q345'); // false
isNumber(null); // false
isNumber(undefined); // false
isNumber(false); // false
isNumber(' '); // false
Solution 3:
The best way I have found is to either check for a method on the string, i.e.:
if (x.substring) {
// do string thing
} else{
// do other thing
}
or if you want to do something with the number check for a number property,
if (x.toFixed) {
// do number thing
} else {
// do other thing
}
This is sort of like "duck typing", it's up to you which way makes the most sense. I don't have enough karma to comment, but typeof fails for boxed strings and numbers, i.e.:
alert(typeof new String('Hello World'));
alert(typeof new Number(5));
will alert "object".
Solution 4:
You're looking for isNaN()
:
console.log(!isNaN(123));
console.log(!isNaN(-1.23));
console.log(!isNaN(5-2));
console.log(!isNaN(0));
console.log(!isNaN("0"));
console.log(!isNaN("2"));
console.log(!isNaN("Hello"));
console.log(!isNaN("2005/12/12"));
See JavaScript isNaN() Function at MDN.
Solution 5:
Since ES2015 the correct way to check if a variable
holds a valid number is Number.isFinite(value)
Examples:
Number.isFinite(Infinity) // false
Number.isFinite(NaN) // false
Number.isFinite(-Infinity) // false
Number.isFinite(0) // true
Number.isFinite(2e64) // true
Number.isFinite('0') // false
Number.isFinite(null) // false