How to run a shell script at startup
On an Amazon S3 Linux instance, I have two scripts called start_my_app
and stop_my_app
which start and stop forever (which in turn runs my Node.js application). I use these scripts to manually start and stop my Node.js application. So far so good.
My problem: I also want to set it up such that start_my_app
is run whenever the system boots up. I know that I need to add a file inside init.d
and I know how to symlink it to the proper directory within rc.d
, but I can't figure out what actually needs to go inside the file that I place in init.d
. I'm thinking it should be just one line, like, start_my_app
, but that hasn't been working for me.
Set a crontab for this
#crontab -e
@reboot /home/user/test.sh
after every startup it will run the test script.
In the file you put in /etc/init.d/
you have to set it executable with:
chmod +x /etc/init.d/start_my_app
Thanks to @meetamit, if this does not run you have to create a symlink to /etc/rc.d/
ln -s /etc/init.d/start_my_app /etc/rc.d/
Please note that on latest Debian, this will not work as your script have to be LSB compliant (provide, at least, the following actions: start, stop, restart, force-reload, and status): https://wiki.debian.org/LSBInitScripts
As a note, you should put the absolute path of your script instead of a relative one, it may solves unexpected issues:
/var/myscripts/start_my_app
And don't forget to add on top of that file:
#!/bin/sh