Why is $1/i$ equal to $-i$?
$$\frac{1}{i}=\frac{i}{i^2}=\frac{i}{-1}=-i$$
Note that $i(-i)=1$. By definition, this means that $(1/i)=-i$.
The notation "$i$ raised to the power $-1$" denotes the element that multiplied by $i$ gives the multiplicative identity: $1$.
In fact, $-i$ satisfies that since
$$(-i)\cdot i= -(i\cdot i)= -(-1) =1$$
That notation holds in general. For example, $2^{-1}=\frac{1}{2}$ since $\frac{1}{2}$ is the number that gives $1$ when multiplied by $2$.