UITableView with images scrolls very slowly [duplicate]
Possible Duplicate:
Table View with Images, slow load and scroll
I have a UITableView
which downloads images for the UITableViewCells
from a server.
I observed that the tableView scrolls very slowly.
I thought that this might downloading problem, but I have realized that the table still scrolls slowly after download has finished and the image icon size is less.
I searched Google but couldn't find any help.
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
btnBack.hidden = FALSE;
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil)
{
cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];
cell.selectionStyle = UITableViewCellSelectionStyleNone;
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
cell.backgroundColor = [UIColor clearColor];
cell.textLabel.font = [UIFont fontWithName:@"Noteworthy" size:17.0];
cell.textLabel.font = [UIFont boldSystemFontOfSize:17.0];
cell.textLabel.textColor = [UIColor blackColor];
cell.textLabel.highlightedTextColor = [UIColor blackColor];
}
cell.textLabel.text = [NSString stringWithFormat:@" %@", [test.arrTitle objectAtIndex:indexPath.row]];
NSString *Path;
Path = [NSString stringWithFormat:@"http://%@",[test.arrImages objectAtIndex:indexPath.row]];
NSLog(@"image-->%@",[test.arrImages objectAtIndex:indexPath.row]);
NSString *strImage = Path;
NSURL *url4Image = [NSURL URLWithString:strImage];
NSData *data = [NSData dataWithContentsOfURL:url4Image];
image =[[UIImage alloc] initWithData:data];
cell.imageView.image =image;
[image release];
return cell;
}
Solution 1:
While my original answer, below, attempted to solve several key problems associated with asynchronous image retrieval, it is still fundamentally limited. A proper implementation would also make sure that if you scrolled quickly, that the visible cells were prioritized over cells that had scrolled off screen. It would also support cancelation of prior requests (and canceled them for you when appropriate).
While we could add these sorts of capabilities to the below code, it is probably better to adopt an established, proven solution that utilizes the NSOperationQueue
and NSCache
technologies discussed below, but also addresses the above issues. The easiest solution is to adopt one of the established UIImageView
categories that supports asynchronous image retrieval. The AFNetworking and SDWebImage libraries both have UIImageView
categories that gracefully handle all of these issues.
You can use NSOperationQueue
or GCD to do your lazy loading (see Concurrency Programming Guide for discussion of different asynchronous operations technologies). The former enjoys an advantage that you can specify precisely how many concurrent operations are permissible, which is very important in loading images from the web because many web servers limit how many concurrent requests they will accept from a given client.
The basic idea is:
- Submit request of the image data in a separate background queue;
- When done downloading image, dispatch UI update back to main queue because you should never do UI updates in the background;
- When running dispatched final UI update code on main queue, make sure the
UITableViewCell
is still visible and that it hasn't been dequeued and reused because the cell in question scrolled off the screen. If you don't do that, the wrong image may momentarily show up.
You would want to replace your code with something like the following code:
First, define a property for your NSOperationQueue
that you will use for downloading images, as well as a NSCache
for storing those images:
@property (nonatomic, strong) NSOperationQueue *imageDownloadingQueue;
@property (nonatomic, strong) NSCache *imageCache;
Second, initialize this queue and cache in viewDidLoad
:
- (void)viewDidLoad
{
[super viewDidLoad];
self.imageDownloadingQueue = [[NSOperationQueue alloc] init];
self.imageDownloadingQueue.maxConcurrentOperationCount = 4; // many servers limit how many concurrent requests they'll accept from a device, so make sure to set this accordingly
self.imageCache = [[NSCache alloc] init];
// the rest of your viewDidLoad
}
Third, your cellForRowAtIndexPath
might look like:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
btnBack.hidden = FALSE;
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];
cell.selectionStyle = UITableViewCellSelectionStyleNone;
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
cell.backgroundColor = [UIColor clearColor];
cell.textLabel.font = [UIFont fontWithName:@"Noteworthy" size:17.0];
cell.textLabel.font = [UIFont boldSystemFontOfSize:17.0];
cell.textLabel.textColor = [UIColor blackColor];
cell.textLabel.highlightedTextColor = [UIColor blackColor];
}
cell.textLabel.text = [NSString stringWithFormat:@" %@", [test.arrTitle objectAtIndex:indexPath.row]];
// code change starts here ... initialize image and then do image loading in background
NSString *imageUrlString = [NSString stringWithFormat:@"http://%@", [test.arrImages objectAtIndex:indexPath.row]];
UIImage *cachedImage = [self.imageCache objectForKey:imageUrlString];
if (cachedImage) {
cell.imageView.image = cachedImage;
} else {
// you'll want to initialize the image with some blank image as a placeholder
cell.imageView.image = [UIImage imageNamed:@"blankthumbnail.png"];
// now download in the image in the background
[self.imageDownloadingQueue addOperationWithBlock:^{
NSURL *imageUrl = [NSURL URLWithString:imageUrlString];
NSData *imageData = [NSData dataWithContentsOfURL:imageUrl];
UIImage *image = nil;
if (imageData)
image = [UIImage imageWithData:imageData];
if (image) {
// add the image to your cache
[self.imageCache setObject:image forKey:imageUrlString];
// finally, update the user interface in the main queue
[[NSOperationQueue mainQueue] addOperationWithBlock:^{
// Make sure the cell is still visible
// Note, by using the same `indexPath`, this makes a fundamental
// assumption that you did not insert any rows in the intervening
// time. If this is not a valid assumption, make sure you go back
// to your model to identify the correct `indexPath`/`updateCell`
UITableViewCell *updateCell = [tableView cellForRowAtIndexPath:indexPath];
if (updateCell)
updateCell.imageView.image = image;
}];
}
}];
}
return cell;
}
Fourth, and finally, while one might be inclined to write code to purge the cache in low memory situations, it turns out that it does this automatically, so no extra handling is needed here. If you manually simulate a low memory situation in the simulator, you won't see it evict its objects because Actually, NSCache
doesn't respond UIApplicationDidReceiveMemoryWarningNotification
, but during actual operation, when memory is low, the cache will be purged.NSCache
no longer gracefully responds to low memory situations itself, so you really should add observer for this notification and empty the cache in low memory situations.
I might suggest a bunch of other optimizations (e.g. perhaps also caching images into persistent storage to streamline future operations; I actually put all of this logic in my own AsyncImage
class), but first see if this solves the basic performance issue.
Solution 2:
Write this in your UITableView
cellForRowAtIndex:
Method
asyncImageView = [[AsyncImageView alloc]initWithFrame:CGRectMake(30,32,100, 100)];
[asyncImageView loadImageFromURL:[NSURL URLWithString:your url]];
[cell addSubview:asyncImageView];
[asyncImageView release];
Need to import AsyncImageView class
and create Object For that Class