Do we have closures in C++?
Solution 1:
The latest C++ standard, C++11, has closures.
http://en.wikipedia.org/wiki/C%2B%2B11#Lambda_functions_and_expressions
http://www.cprogramming.com/c++11/c++11-lambda-closures.html
Solution 2:
If you understand closure as a reference to a function that has an embedded, persistent, hidden and unseparable context (memory, state), then yes:
class add_offset {
private:
int offset;
public:
add_offset(int _offset) : offset(_offset) {}
int operator () (int x) { return x + offset; }
}
// make a closure
add_offset my_add_3_closure(3);
// use closure
int x = 4;
int y = my_add_3_closure(x);
std::cout << y << std::endl;
The next one modifies its state:
class summer
{
private:
int sum;
public:
summer() : sum(0) {}
int operator () (int x) { return sum += x; }
}
// make a closure
summer adder;
// use closure
adder(3);
adder(4);
std::cout << adder(0) << std::endl;
The inner state can not be referenced (accessed) from outside.
Depending on how you define it, a closure can contain a reference to more than one function or, two closures can share the same context, i.e. two functions can share the same persistent state.
Closure means not containing free variables - it is comparable to a class with only private attributes and only public method(s).
Solution 3:
Yes, This shows how you could implement a function with a state without using a functor.
#include <iostream>
#include <functional>
std::function<int()> make_my_closure(int x){
return [x]() mutable {
++x;
return x;
};
}
int main()
{
auto my_f = make_my_closure(10);
std::cout << my_f() << std::endl; // 11
std::cout << my_f() << std::endl; // 12
std::cout << my_f() << std::endl; // 13
auto my_f1 = make_my_closure(1);
std::cout << my_f1() << std::endl; // 2
std::cout << my_f1() << std::endl; // 3
std::cout << my_f1() << std::endl; // 4
std::cout << my_f() << std::endl; // 14
}
I forgot the mutable keyword which introduced an undefined behaviour (clang version was returning a garbage value). As implemented, the closure works fine (on GCC and clang)