How can I check if a value is of type Integer?

If input value can be in numeric form other than integer , check by

if (x == (int)x)
{
   // Number is integer
}

If string value is being passed , use Integer.parseInt(string_var). Please ensure error handling using try catch in case conversion fails.


If you have a double/float/floating point number and want to see if it's an integer.

public boolean isDoubleInt(double d)
{
    //select a "tolerance range" for being an integer
    double TOLERANCE = 1E-5;
    //do not use (int)d, due to weird floating point conversions!
    return Math.abs(Math.floor(d) - d) < TOLERANCE;
}

If you have a string and want to see if it's an integer. Preferably, don't throw out the Integer.valueOf() result:

public boolean isStringInt(String s)
{
    try
    {
        Integer.parseInt(s);
        return true;
    } catch (NumberFormatException ex)
    {
        return false;
    }
}

If you want to see if something is an Integer object (and hence wraps an int):

public boolean isObjectInteger(Object o)
{
    return o instanceof Integer;
}

if (x % 1 == 0)
    // x is an integer

Here x is a numeric primitive: short, int, long, float or double


Try maybe this way

try{
    double d= Double.valueOf(someString);
    if (d==(int)d){
        System.out.println("integer"+(int)d);
    }else{
        System.out.println("double"+d);
    }
}catch(Exception e){
    System.out.println("not number");
}

But all numbers outside Integers range (like "-1231231231231231238") will be treated as doubles. If you want to get rid of that problem you can try it this way

try {
    double d = Double.valueOf(someString);
    if (someString.matches("\\-?\\d+")){//optional minus and at least one digit
        System.out.println("integer" + d);
    } else {
        System.out.println("double" + d);
    }
} catch (Exception e) {
    System.out.println("not number");
}

You should use the instanceof operator to determine if your value is Integer or not;

Object object = your_value;

if(object instanceof Integer) {

Integer integer = (Integer) object ;

} else {
 //your value isn't integer
}