jQuery draggable + droppable: how to snap dropped element to dropped-on element

I found that Keith's method worked for me. Since his answer doesn't include an example implementation, I'll post mine:

$('.dropTarget').droppable({
    drop: function(ev, ui) {
        var dropped = ui.draggable;
        var droppedOn = $(this);
        $(dropped).detach().css({top: 0,left: 0}).appendTo(droppedOn);
    }
});

or, slightly more concisely:

$('.dropTarget').droppable({
    drop: function(ev, ui) {
        $(ui.draggable).detach().css({top: 0,left: 0}).appendTo(this);
    }
});

I had a similar problem - I worked around it by manually removing the dragged element from its old parent and adding it to the dropped on element.

Thanks for your post - it helped me in the right direction. I find it a bit cleaner to set the position properties of the draggable object instead of messing with the HTML code. This sets the position to the top left corner of the droppable object, but you can modify to have it centered as well.

drop: function(event, ui) {
   $(ui.draggable).css('top', $(this).position().top);
   $(ui.draggable).css('left', $(this).position().left);
}