How can I tail a log file in Python?
Solution 1:
Non Blocking
If you are on linux (as windows does not support calling select on files) you can use the subprocess module along with the select module.
import time
import subprocess
import select
f = subprocess.Popen(['tail','-F',filename],\
stdout=subprocess.PIPE,stderr=subprocess.PIPE)
p = select.poll()
p.register(f.stdout)
while True:
if p.poll(1):
print f.stdout.readline()
time.sleep(1)
This polls the output pipe for new data and prints it when it is available. Normally the time.sleep(1)
and print f.stdout.readline()
would be replaced with useful code.
Blocking
You can use the subprocess module without the extra select module calls.
import subprocess
f = subprocess.Popen(['tail','-F',filename],\
stdout=subprocess.PIPE,stderr=subprocess.PIPE)
while True:
line = f.stdout.readline()
print line
This will also print new lines as they are added, but it will block until the tail program is closed, probably with f.kill()
.
Solution 2:
Using the sh module (pip install sh):
from sh import tail
# runs forever
for line in tail("-f", "/var/log/some_log_file.log", _iter=True):
print(line)
[update]
Since sh.tail with _iter
=True is a generator, you can:
import sh
tail = sh.tail("-f", "/var/log/some_log_file.log", _iter=True)
Then you can "getNewData" with:
new_data = tail.next()
Note that if the tail buffer is empty, it will block until there is more data (from your question it is not clear what you want to do in this case).
[update]
This works if you replace -f with -F, but in Python it would be locking. I'd be more interested in having a function I could call to get new data when I want it, if that's possible. – Eli
A container generator placing the tail call inside a while True loop and catching eventual I/O exceptions will have almost the same effect of -F.
def tail_F(some_file):
while True:
try:
for line in sh.tail("-f", some_file, _iter=True):
yield line
except sh.ErrorReturnCode_1:
yield None
If the file becomes inaccessible, the generator will return None. However it still blocks until there is new data if the file is accessible. It remains unclear for me what you want to do in this case.
Raymond Hettinger approach seems pretty good:
def tail_F(some_file):
first_call = True
while True:
try:
with open(some_file) as input:
if first_call:
input.seek(0, 2)
first_call = False
latest_data = input.read()
while True:
if '\n' not in latest_data:
latest_data += input.read()
if '\n' not in latest_data:
yield ''
if not os.path.isfile(some_file):
break
continue
latest_lines = latest_data.split('\n')
if latest_data[-1] != '\n':
latest_data = latest_lines[-1]
else:
latest_data = input.read()
for line in latest_lines[:-1]:
yield line + '\n'
except IOError:
yield ''
This generator will return '' if the file becomes inaccessible or if there is no new data.
[update]
The second to last answer circles around to the top of the file it seems whenever it runs out of data. – Eli
I think the second will output the last ten lines whenever the tail process ends, which with -f
is whenever there is an I/O error. The tail --follow --retry
behavior is not far from this for most cases I can think of in unix-like environments.
Perhaps if you update your question to explain what is your real goal (the reason why you want to mimic tail --retry), you will get a better answer.
The last answer does not actually follow the tail and merely reads what's available at run time. – Eli
Of course, tail will display the last 10 lines by default... You can position the file pointer at the end of the file using file.seek, I will left a proper implementation as an exercise to the reader.
IMHO the file.read() approach is far more elegant than a subprocess based solution.
Solution 3:
The only portable way to tail -f
a file appears to be, in fact, to read from it and retry (after a sleep
) if the read
returns 0. The tail
utilities on various platforms use platform-specific tricks (e.g. kqueue
on BSD) to efficiently tail a file forever without needing sleep
.
Therefore, implementing a good tail -f
purely in Python is probably not a good idea, since you would have to use the least-common-denominator implementation (without resorting to platform-specific hacks). Using a simple subprocess
to open tail -f
and iterating through the lines in a separate thread, you can easily implement a non-blocking tail
operation in Python.
Example implementation:
import threading, Queue, subprocess
tailq = Queue.Queue(maxsize=10) # buffer at most 100 lines
def tail_forever(fn):
p = subprocess.Popen(["tail", "-f", fn], stdout=subprocess.PIPE)
while 1:
line = p.stdout.readline()
tailq.put(line)
if not line:
break
threading.Thread(target=tail_forever, args=(fn,)).start()
print tailq.get() # blocks
print tailq.get_nowait() # throws Queue.Empty if there are no lines to read
Solution 4:
Purely pythonic solution using non-blocking readline()
Adapting Ijaz Ahmad Khan's answer to only yield lines when they are completely written (lines end with a newline char) gives a pythonic solution with no external dependencies:
def follow(file, sleep_sec=0.1) -> Iterator[str]:
""" Yield each line from a file as they are written.
`sleep_sec` is the time to sleep after empty reads. """
line = ''
while True:
tmp = file.readline()
if tmp is not None:
line += tmp
if line.endswith("\n"):
yield line
line = ''
else if sleep_sec:
time.sleep(sleep_sec)
if __name__ == '__main__':
with open("test.txt", 'r') as file:
for line in follow(file):
print(line, end='')