How to call through a member function pointer?
I'm trying to do some testing with member function pointer. What is wrong with this code? The bigCat.*pcat();
statement doesn't compile.
class cat {
public:
void walk() {
printf("cat is walking \n");
}
};
int main(){
cat bigCat;
void (cat::*pcat)();
pcat = &cat::walk;
bigCat.*pcat();
}
More parentheses are required:
(bigCat.*pcat)();
^ ^
The function call (()
) has higher precedence than the pointer-to-member binding operator (.*
). The unary operators have higher precedence than the binary operators.
Today, the canonical way is using the std::invoke function template, especially in generic code. Please note, that the member function pointer comes first:
import <functional>;
std::invoke(pcat, bigCat);
What you get: Unified calling syntax for virtually anything, that is invocable.
Overhead: none.