How to parse number string containing commas into an integer in java?

Solution 1:

Is this comma a decimal separator or are these two numbers? In the first case you must provide Locale to NumberFormat class that uses comma as decimal separator:

NumberFormat.getNumberInstance(Locale.FRANCE).parse("265,858")

This results in 265.858. But using US locale you'll get 265858:

NumberFormat.getNumberInstance(java.util.Locale.US).parse("265,858")

That's because in France they treat comma as decimal separator while in US - as grouping (thousand) separator.

If these are two numbers - String.split() them and parse two separate strings independently.

Solution 2:

You can remove the , before parsing it to an int:

int i = Integer.parseInt(myNumberString.replaceAll(",", ""));

Solution 3:

If it is one number & you want to remove separators, NumberFormat will return a number to you. Just make sure to use the correct Locale when using the getNumberInstance method.

For instance, some Locales swap the comma and decimal point to what you may be used to.

Then just use the intValue method to return an integer. You'll have to wrap the whole thing in a try/catch block though, to account for Parse Exceptions.

try {
    NumberFormat ukFormat = NumberFormat.getNumberInstance(Locale.UK);
    ukFormat.parse("265,858").intValue();
} catch(ParseException e) {
    //Handle exception
}