Site matching query does not exist
If you don't have a site defined in your database and django wants to reference it, you will need to create one.
From a python manage.py shell
:
from django.contrib.sites.models import Site
new_site = Site.objects.create(domain='foo.com', name='foo.com')
print (new_site.id)
Now set that site ID in your settings.py to SITE_ID
Table django_site
must contain a row with the same value than id
(by default equals to 1
), as SITE_ID
is set to (inside your settings.py
).
Add SITE_ID = 1
to settings.py in your django project.
I fixed it without using python manage.py
shell
At first I tried using the commands above using manage.py
shell:
from django.contrib.sites.models import Site
new_site = Site.objects.create(domain='foo.com', name='foo.com')
print(new_site.id)
But it gave out an INTEGRITY ERROR
The short answer is add SITE_ID = 1
to your settings.py
If you want to know what your site id is, then go into the actual database, I downloaded sqliteman to see what my table had. So whatever site id you have in the table is what gets assigned to SITE_ID
This is because there is a function get_current
that goes looking for SITE_ID
and it doesn't find it in your settings.py
tables
-django_site
--Columns
---id
it should have id as 1, name as example.com
, domain as example.com