Is there a way to provide named parameters in a function call in JavaScript?

Solution 1:

ES2015 and later

In ES2015, parameter destructuring can be used to simulate named parameters. It would require the caller to pass an object, but you can avoid all of the checks inside the function if you also use default parameters:

myFunction({ param1 : 70, param2 : 175});

function myFunction({param1, param2}={}){
  // ...function body...
}

// Or with defaults, 
function myFunc({
  name = 'Default user',
  age = 'N/A'
}={}) {
  // ...function body...
}

ES5

There is a way to come close to what you want, but it is based on the output of Function.prototype.toString ^[ES5], which is implementation dependent to some degree, so it might not be cross-browser compatible.

The idea is to parse the parameter names from the string representation of the function so that you can associate the properties of an object with the corresponding parameter.

A function call could then look like

func(a, b, {someArg: ..., someOtherArg: ...});

where a and b are positional arguments and the last argument is an object with named arguments.

For example:

var parameterfy = (function() {
    var pattern = /function[^(]*\(([^)]*)\)/;

    return function(func) {
        // fails horribly for parameterless functions ;)
        var args = func.toString().match(pattern)[1].split(/,\s*/);

        return function() {
            var named_params = arguments[arguments.length - 1];
            if (typeof named_params === 'object') {
                var params = [].slice.call(arguments, 0, -1);
                if (params.length < args.length) {
                    for (var i = params.length, l = args.length; i < l; i++) {
                        params.push(named_params[args[i]]);
                    }
                    return func.apply(this, params);
                }
            }
            return func.apply(null, arguments);
        };
    };
}());

Which you would use as:

var foo = parameterfy(function(a, b, c) {
    console.log('a is ' + a, ' | b is ' + b, ' | c is ' + c);     
});

foo(1, 2, 3); // a is 1  | b is 2  | c is 3
foo(1, {b:2, c:3}); // a is 1  | b is 2  | c is 3
foo(1, {c:3}); // a is 1  | b is undefined  | c is 3
foo({a: 1, c:3}); // a is 1  | b is undefined  | c is 3 

DEMO

There are some drawbacks to this approach (you have been warned!):

• If the last argument is an object, it is treated as a "named argument objects"
• You will always get as many arguments as you defined in the function, but some of them might have the value undefined (that's different from having no value at all). That means you cannot use arguments.length to test how many arguments have been passed.

Instead of having a function creating the wrapper, you could also have a function which accepts a function and various values as arguments, such as

call(func, a, b, {posArg: ... });

or even extend Function.prototype so that you could do:

foo.execute(a, b, {posArg: ...});

Solution 2:

No - the object approach is JavaScript's answer to this. There is no problem with this provided your function expects an object rather than separate params.