Create mutable List from array?

One simple way:

Foo[] array = ...;
List<Foo> list = new ArrayList<Foo>(Arrays.asList(array));

That will create a mutable list - but it will be a copy of the original array. Changing the list will not change the array. You can copy it back later, of course, using toArray.

If you want to create a mutable view onto an array, I believe you'll have to implement that yourself.

And if you are using google collection API's (Guava):

Lists.newArrayList(myArray);

This simple code using the Stream API included in Java 8 creates a mutable list (or view) containing the elements of your array:

Foo[] array = ...;
List<Foo> list = Stream.of(array).collect(Collectors.toCollection(ArrayList::new));

Or, equally valid:

List<Foo> list = Arrays.stream(array).collect(Collectors.toCollection(ArrayList::new));

If you're using Eclipse Collections (formerly GS Collections), you can use FastList.newListWith(...) or FastList.wrapCopy(...).

Both methods take varargs, so you can create the array inline or pass in an existing array.

MutableList<Integer> list1 = FastList.newListWith(1, 2, 3, 4);

Integer[] array2 = {1, 2, 3, 4};
MutableList<Integer> list2 = FastList.newListWith(array2);

The difference between the two methods is whether or not the array gets copied. newListWith() doesn't copy the array and thus takes constant time. You should avoid using it if you know the array could be mutated elsewhere.

Integer[] array2 = {1, 2, 3, 4};
MutableList<Integer> list2 = FastList.newListWith(array2);
array2[1] = 5;
Assert.assertEquals(FastList.newListWith(1, 5, 3, 4), list2);

Integer[] array3 = {1, 2, 3, 4};
MutableList<Integer> list3 = FastList.wrapCopy(array3);
array3[1] = 5;
Assert.assertEquals(FastList.newListWith(1, 2, 3, 4), list3);

Note: I am a committer for Eclipse Collections.