What is the difference between vmalloc and kmalloc?

I've googled around and found most people advocating the use of kmalloc, as you're guaranteed to get contiguous physical blocks of memory. However, it also seems as though kmalloc can fail if a contiguous physical block that you want can't be found.
What are the advantages of having a contiguous block of memory? Specifically, why would I need to have a contiguous physical block of memory in a system call? Is there any reason I couldn't just use vmalloc?
Finally, if I were to allocate memory during the handling of a system call, should I specify GFP_ATOMIC? Is a system call executed in an atomic context?

GFP_ATOMIC
The allocation is high-priority and does not sleep. This is the flag to use in interrupt handlers, bottom halves and other situations where you cannot sleep.

GFP_KERNEL This is a normal allocation and might block. This is the flag to use in process context code when it is safe to sleep.

Solution 1:

You only need to worry about using physically contiguous memory if the buffer will be accessed by a DMA device on a physically addressed bus (like PCI). The trouble is that many system calls have no way to know whether their buffer will eventually be passed to a DMA device: once you pass the buffer to another kernel subsystem, you really cannot know where it is going to go. Even if the kernel does not use the buffer for DMA today, a future development might do so.

vmalloc is often slower than kmalloc, because it may have to remap the buffer space into a virtually contiguous range. kmalloc never remaps, though if not called with GFP_ATOMIC kmalloc can block.

kmalloc is limited in the size of buffer it can provide: 128 KBytes^*). If you need a really big buffer, you have to use vmalloc or some other mechanism like reserving high memory at boot.

^*)This was true of earlier kernels. On recent kernels (I tested this on 2.6.33.2), max size of a single kmalloc is up to 4 MB! (I wrote a fairly detailed post on this.) — kaiwan

For a system call you don't need to pass GFP_ATOMIC to kmalloc(), you can use GFP_KERNEL. You're not an interrupt handler: the application code enters the kernel context by means of a trap, it is not an interrupt.

Solution 2:

Short answer: download Linux Device Drivers and read the chapter on memory management.

Seriously, there are a lot of subtle issues related to kernel memory management that you need to understand - I spend a lot of my time debugging problems with it.

vmalloc() is very rarely used, because the kernel rarely uses virtual memory. kmalloc() is what is typically used, but you have to know what the consequences of the different flags are and you need a strategy for dealing with what happens when it fails - particularly if you're in an interrupt handler, like you suggested.

Solution 3:

Linux Kernel Development by Robert Love (Chapter 12, page 244 in 3rd edition) answers this very clearly.

Yes, physically contiguous memory is not required in many of the cases. Main reason for kmalloc being used more than vmalloc in kernel is performance. The book explains, when big memory chunks are allocated using vmalloc, kernel has to map the physically non-contiguous chunks (pages) into a single contiguous virtual memory region. Since the memory is virtually contiguous and physically non-contiguous, several virtual-to-physical address mappings will have to be added to the page table. And in the worst case, there will be (size of buffer/page size) number of mappings added to the page table.

This also adds pressure on TLB (the cache entries storing recent virtual to physical address mappings) when accessing this buffer. This can lead to thrashing.