Access maven properties defined in the pom
Solution 1:
Use the properties-maven-plugin to write specific pom properties
to a file at compile time, and then read that file at run time.
In your pom.xml:
<properties>
<name>${project.name}</name>
<version>${project.version}</version>
<foo>bar</foo>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>properties-maven-plugin</artifactId>
<version>1.0.0</version>
<executions>
<execution>
<phase>generate-resources</phase>
<goals>
<goal>write-project-properties</goal>
</goals>
<configuration>
<outputFile>${project.build.outputDirectory}/my.properties</outputFile>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
And then in .java:
java.io.InputStream is = this.getClass().getResourceAsStream("my.properties");
java.util.Properties p = new Properties();
p.load(is);
String name = p.getProperty("name");
String version = p.getProperty("version");
String foo = p.getProperty("foo");
Solution 2:
Set up a System variable from Maven and in java use following call
System.getProperty("Key");
Solution 3:
Maven already has a solution to do what you want:
Get MavenProject from just the POM.xml - pom parser?
btw: first hit at google search ;)
Model model = null;
FileReader reader = null;
MavenXpp3Reader mavenreader = new MavenXpp3Reader();
try {
reader = new FileReader(pomfile); // <-- pomfile is your pom.xml
model = mavenreader.read(reader);
model.setPomFile(pomfile);
}catch(Exception ex){
// do something better here
ex.printStackTrace()
}
MavenProject project = new MavenProject(model);
project.getProperties() // <-- thats what you need
Solution 4:
This can be done with standard java properties in combination with the maven-resource-plugin
with enabled filtering on properties.
For more info see http://maven.apache.org/plugins/maven-resources-plugin/examples/filter.html
This will work for standard maven project as for plugin projects