Redirect subprocess stderr to stdout

A close read of the source code gives the answer. In particular, the documentation is misleading when it says:

subprocess.STDOUT
Special value that (...) indicates that standard error should go into the same handle as standard output.

Since stdout is set to "default" (-1, technically) when stderr=subprocess.STDOUT is evaluated, stderr is set to "default" as well. Unfortunately, this means that stderr output still goes to stderr.

To solve the problem, pass in the stdout file instead of subprocess.STDOUT:

$ python >/dev/null -c 'import subprocess,sys;subprocess.call(["ls", "/404"],
                        stderr=sys.stdout.buffer)'

Or, for compatibility with legacy 2.x versions of Python:

$ python >/dev/null -c 'import subprocess,sys;subprocess.call(["ls", "/404"],
                        stderr=sys.stdout.fileno())'

Actually, using subprocess.STDOUT does exactly what is stated in the documentation: it redirects stderr to stdout so that e.g.

proc = subprocess.Popen(self.task["command"], shell=False, bufsize=1, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
output = ""
while (True):
    # Read line from stdout, break if EOF reached, append line to output
    line = proc.stdout.readline()
    line = line.decode()
    if (line == ""): break
    output += line

results in variable output containing the process' output from both stdout and stderr.

stderr=subprocess.STDOUT redirects all stderr output directly to stdout of the calling process, which is a major difference.

Redirect subprocess stderr to stdout

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