Convert integer to hexadecimal and back again

Solution 1:

// Store integer 182
int intValue = 182;
// Convert integer 182 as a hex in a string variable
string hexValue = intValue.ToString("X");
// Convert the hex string back to the number
int intAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);

from http://www.geekpedia.com/KB8_How-do-I-convert-from-decimal-to-hex-and-hex-to-decimal.html

HINT (from the comments):

Use .ToString("X4") to get exactly 4 digits with leading 0, or .ToString("x4") for lowercase hex numbers (likewise for more digits).

Solution 2:

Use:

int myInt = 2934;
string myHex = myInt.ToString("X");  // Gives you hexadecimal
int myNewInt = Convert.ToInt32(myHex, 16);  // Back to int again.

See How to: Convert Between Hexadecimal Strings and Numeric Types (C# Programming Guide) for more information and examples.

Solution 3:

Try the following to convert it to hex

public static string ToHex(this int value) {
  return String.Format("0x{0:X}", value);
}

And back again

public static int FromHex(string value) {
  // strip the leading 0x
  if ( value.StartsWith("0x", StringComparison.OrdinalIgnoreCase)) {
    value = value.Substring(2);
  }
  return Int32.Parse(value, NumberStyles.HexNumber);
}

Solution 4:

int valInt = 12;
Console.WriteLine(valInt.ToString("X"));  // C  ~ possibly single-digit output 
Console.WriteLine(valInt.ToString("X2")); // 0C ~ always double-digit output