How to remove any URL within a string in Python

Solution 1:

the shortest way

re.sub(r'http\S+', '', stringliteral)

Solution 2:

Python script:

import re
text = re.sub(r'^https?:\/\/.*[\r\n]*', '', text, flags=re.MULTILINE)

Output:

text1
text2
text3
text4
text5
text6

Test this code here.

Solution 3:

This worked for me:

import re
thestring = "text1\ntext2\nhttp://url.com/bla1/blah1/\ntext3\ntext4\nhttp://url.com/bla2/blah2/\ntext5\ntext6"

URLless_string = re.sub(r'\w+:\/{2}[\d\w-]+(\.[\d\w-]+)*(?:(?:\/[^\s/]*))*', '', thestring)
print URLless_string

Result:

text1
text2

text3
text4

text5
text6

Solution 4:

Removal of HTTP links/URLs mixed up in any text:

import re
re.sub(r'''(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'".,<>?«»“”‘’]))''', " ", text)

Solution 5:

This solution caters for http, https and the other normal url type special characters :

import re
def remove_urls (vTEXT):
    vTEXT = re.sub(r'(https|http)?:\/\/(\w|\.|\/|\?|\=|\&|\%)*\b', '', vTEXT, flags=re.MULTILINE)
    return(vTEXT)


print( remove_urls("this is a test https://sdfs.sdfsdf.com/sdfsdf/sdfsdf/sd/sdfsdfs?bob=%20tree&jef=man lets see this too https://sdfsdf.fdf.com/sdf/f end"))