Python inheritance: TypeError: object.__init__() takes no parameters
Solution 1:
You are calling the wrong class name in your super() call:
class SimpleHelloWorld(IRCReplyModule):
def __init__(self):
#super(IRCReplyModule,self).__init__('hello world')
super(SimpleHelloWorld,self).__init__('hello world')
Essentially what you are resolving to is the __init__
of the object base class which takes no params.
Its a bit redundant, I know, to have to specify the class that you are already inside of, which is why in python3 you can just do: super().__init__()
Solution 2:
This has bitten me twice recently (I know I should have learned from my mistake the first time) and the accepted answer hasn't helped me either time so while it is fresh in my mind I thought I would submit my own answer just in case anybody else is running into this (or I need this again in future).
In my case the issue was that I was passing a kwarg into the initialisation of the subclass but in the superclass that keyword arg was then being passed though into the super() call.
I always think these types of things are best with an example:
class Foo(object):
def __init__(self, required_param_1, *args, **kwargs):
super(Foo, self).__init__(*args, **kwargs)
self.required_param = required_param_1
self.some_named_optional_param = kwargs.pop('named_optional_param', None)
def some_other_method(self):
raise NotImplementedException
class Bar(Foo):
def some_other_method(self):
print('Do some magic')
Bar(42) # no error
Bar(42, named_optional_param={'xyz': 123}) # raises TypeError: object.__init__() takes no parameters
So to resolve this I just need to alter the order that I do things in the Foo.__init__ method; e.g.:
class Foo(object):
def __init__(self, required_param_1, *args, **kwargs):
self.some_named_optional_param = kwargs.pop('named_optional_param', None)
# call super only AFTER poping the kwargs
super(Foo, self).__init__(*args, **kwargs)
self.required_param = required_param_1