Grab a segment of an array in Java without creating a new array on heap

I'm looking for a method in Java that will return a segment of an array. An example would be to get the byte array containing the 4th and 5th bytes of a byte array. I don't want to have to create a new byte array in the heap memory just to do that. Right now I have the following code:

doSomethingWithTwoBytes(byte[] twoByteArray);

void someMethod(byte[] bigArray)
{
      byte[] x = {bigArray[4], bigArray[5]};
      doSomethingWithTwoBytes(x);
}

I'd like to know if there was a way to just do doSomething(bigArray.getSubArray(4, 2)) where 4 is the offset and 2 is the length, for example.

Disclaimer: This answer does not conform to the constraints of the question:

I don't want to have to create a new byte array in the heap memory just to do that.

(Honestly, I feel my answer is worthy of deletion. The answer by @unique72 is correct. Imma let this edit sit for a bit and then I shall delete this answer.)

I don't know of a way to do this directly with arrays without additional heap allocation, but the other answers using a sub-list wrapper have additional allocation for the wrapper only – but not the array – which would be useful in the case of a large array.

That said, if one is looking for brevity, the utility method Arrays.copyOfRange() was introduced in Java 6 (late 2006?):

byte [] a = new byte [] {0, 1, 2, 3, 4, 5, 6, 7};

// get a[4], a[5]

byte [] subArray = Arrays.copyOfRange(a, 4, 6);

Arrays.asList(myArray) delegates to new ArrayList(myArray), which doesn't copy the array but just stores the reference. Using List.subList(start, end) after that makes a SubList which just references the original list (which still just references the array). No copying of the array or its contents, just wrapper creation, and all lists involved are backed by the original array. (I thought it'd be heavier.)

If you're seeking a pointer style aliasing approach, so that you don't even need to allocate space and copy the data then I believe you're out of luck.

System.arraycopy() will copy from your source to destination, and efficiency is claimed for this utility. You do need to allocate the destination array.

One way is to wrap the array in java.nio.ByteBuffer, use the absolute put/get functions, and slice the buffer to work on a subarray.

For instance:

doSomething(ByteBuffer twoBytes) {
    byte b1 = twoBytes.get(0);
    byte b2 = twoBytes.get(1);
    ...
}

void someMethod(byte[] bigArray) {
      int offset = 4;
      int length = 2;
      doSomething(ByteBuffer.wrap(bigArray, offset, length).slice());
}

Note that you have to call both wrap() and slice(), since wrap() by itself only affects the relative put/get functions, not the absolute ones.

ByteBuffer can be a bit tricky to understand, but is most likely efficiently implemented, and well worth learning.