Extracting a zipfile to memory?
How do I extract a zip to memory?
My attempt (returning None
on .getvalue()
):
from zipfile import ZipFile
from StringIO import StringIO
def extract_zip(input_zip):
return StringIO(ZipFile(input_zip).extractall())
Solution 1:
extractall
extracts to the file system, so you won't get what you want. To extract a file in memory, use the ZipFile.read()
method.
If you really need the full content in memory, you could do something like:
def extract_zip(input_zip):
input_zip=ZipFile(input_zip)
return {name: input_zip.read(name) for name in input_zip.namelist()}
Solution 2:
If you work with in-memory archives frequently, I would recommend making a tool. Something like this:
# Works in Python 2 and 3.
try:
import BytesIO
except ImportError:
from io import BytesIO # Python 3
import zipfile
class InMemoryZip(object):
def __init__(self):
# Create the in-memory file-like object for working w/IMZ
self.in_memory_zip = BytesIO()
# Just zip it, zip it
def append(self, filename_in_zip, file_contents):
# Appends a file with name filename_in_zip and contents of
# file_contents to the in-memory zip.
# Get a handle to the in-memory zip in append mode
zf = zipfile.ZipFile(self.in_memory_zip, "a", zipfile.ZIP_DEFLATED, False)
# Write the file to the in-memory zip
zf.writestr(filename_in_zip, file_contents)
# Mark the files as having been created on Windows so that
# Unix permissions are not inferred as 0000
for zfile in zf.filelist:
zfile.create_system = 0
return self
def read(self):
# Returns a string with the contents of the in-memory zip.
self.in_memory_zip.seek(0)
return self.in_memory_zip.read()
# Zip it, zip it, zip it
def writetofile(self, filename):
# Writes the in-memory zip to a physical file.
with open(filename, "wb") as file:
file.write(self.read())
if __name__ == "__main__":
# Run a test
imz = InMemoryZip()
imz.append("testfile.txt", "Make a test").append("testfile2.txt", "And another one")
imz.writetofile("testfile.zip")
print("testfile.zip created")