Programmatically go back to the previous fragment in the backstack

Say I have an activity that has fragments added programmatically:

private void animateToFragment(Fragment newFragment, String tag) {
    FragmentTransaction ft = getFragmentManager().beginTransaction();
    ft.replace(R.id.fragment_container, newFragment, tag);
    ft.addToBackStack(null);
    ft.commit();
}

What is the best way to return to the previous fragment that was visible?

I found Trigger back-button functionality on button click in Android but I'm thinking simulating a back key event isn't the right way to go about it (and I can't get it to work either):

dispatchKeyEvent(new KeyEvent(KeyEvent.ACTION_DOWN, KeyEvent.KEYCODE_BACK));

Calling finish() just closes the activity which I'm not interested in.

Is there a better way to go about this?

Solution 1:

Look at the getFragmentManager().popBackStack() methods (there are several to choose from)

http://developer.android.com/reference/android/app/FragmentManager.html#popBackStack()

Solution 2:

To elaborate on the other answers provided, this is my solution (placed in an Activity):

@Override
public void onBackPressed(){
    FragmentManager fm = getFragmentManager();
    if (fm.getBackStackEntryCount() > 0) {
        Log.i("MainActivity", "popping backstack");
        fm.popBackStack();
    } else {
        Log.i("MainActivity", "nothing on backstack, calling super");
        super.onBackPressed();  
    }
}

Solution 3:

When we are updating/add the fragments,

Should Include the .addToBackStack().

getSupportFragmentManager().beginTransaction()
    .add(detailFragment, "detail") // Add this transaction to the back stack (name is an optional name for this back stack state, or null).
    .addToBackStack(null)
    .commit();

After that if we give the getFragments.popBackStackImmediate() will return true if we add/update the fragments, and move back to the current screen.

Solution 4:

Android Navigation architecture component.

The following code works for me:

findNavController().popBackStack()