How to extract top-level domain name (TLD) from URL
how would you extract the domain name from a URL, excluding any subdomains?
My initial simplistic attempt was:
'.'.join(urlparse.urlparse(url).netloc.split('.')[-2:])
This works for http://www.foo.com, but not http://www.foo.com.au. Is there a way to do this properly without using special knowledge about valid TLDs (Top Level Domains) or country codes (because they change).
thanks
Solution 1:
Here's a great python module someone wrote to solve this problem after seeing this question: https://github.com/john-kurkowski/tldextract
The module looks up TLDs in the Public Suffix List, mantained by Mozilla volunteers
Quote:
tldextract
on the other hand knows what all gTLDs [Generic Top-Level Domains] and ccTLDs [Country Code Top-Level Domains] look like by looking up the currently living ones according to the Public Suffix List. So, given a URL, it knows its subdomain from its domain, and its domain from its country code.
Solution 2:
No, there is no "intrinsic" way of knowing that (e.g.) zap.co.it
is a subdomain (because Italy's registrar DOES sell domains such as co.it
) while zap.co.uk
isn't (because the UK's registrar DOESN'T sell domains such as co.uk
, but only like zap.co.uk
).
You'll just have to use an auxiliary table (or online source) to tell you which TLD's behave peculiarly like UK's and Australia's -- there's no way of divining that from just staring at the string without such extra semantic knowledge (of course it can change eventually, but if you can find a good online source that source will also change accordingly, one hopes!-).
Solution 3:
Using this file of effective tlds which someone else found on Mozilla's website:
from __future__ import with_statement
from urlparse import urlparse
# load tlds, ignore comments and empty lines:
with open("effective_tld_names.dat.txt") as tld_file:
tlds = [line.strip() for line in tld_file if line[0] not in "/\n"]
def get_domain(url, tlds):
url_elements = urlparse(url)[1].split('.')
# url_elements = ["abcde","co","uk"]
for i in range(-len(url_elements), 0):
last_i_elements = url_elements[i:]
# i=-3: ["abcde","co","uk"]
# i=-2: ["co","uk"]
# i=-1: ["uk"] etc
candidate = ".".join(last_i_elements) # abcde.co.uk, co.uk, uk
wildcard_candidate = ".".join(["*"] + last_i_elements[1:]) # *.co.uk, *.uk, *
exception_candidate = "!" + candidate
# match tlds:
if (exception_candidate in tlds):
return ".".join(url_elements[i:])
if (candidate in tlds or wildcard_candidate in tlds):
return ".".join(url_elements[i-1:])
# returns "abcde.co.uk"
raise ValueError("Domain not in global list of TLDs")
print get_domain("http://abcde.co.uk", tlds)
results in:
abcde.co.uk
I'd appreciate it if someone let me know which bits of the above could be rewritten in a more pythonic way. For example, there must be a better way of iterating over the last_i_elements
list, but I couldn't think of one. I also don't know if ValueError
is the best thing to raise. Comments?
Solution 4:
Using python tld
https://pypi.python.org/pypi/tld
Install
pip install tld
Get the TLD name as string from the URL given
from tld import get_tld
print get_tld("http://www.google.co.uk")
co.uk
or without protocol
from tld import get_tld
get_tld("www.google.co.uk", fix_protocol=True)
co.uk
Get the TLD as an object
from tld import get_tld
res = get_tld("http://some.subdomain.google.co.uk", as_object=True)
res
# 'co.uk'
res.subdomain
# 'some.subdomain'
res.domain
# 'google'
res.tld
# 'co.uk'
res.fld
# 'google.co.uk'
res.parsed_url
# SplitResult(
# scheme='http',
# netloc='some.subdomain.google.co.uk',
# path='',
# query='',
# fragment=''
# )
Get the first level domain name as string from the URL given
from tld import get_fld
get_fld("http://www.google.co.uk")
# 'google.co.uk'
Solution 5:
There are many, many TLD's. Here's the list:
http://data.iana.org/TLD/tlds-alpha-by-domain.txt
Here's another list
http://en.wikipedia.org/wiki/List_of_Internet_top-level_domains
Here's another list
http://www.iana.org/domains/root/db/