Trim whitespace using PIL
Is there a simple solution to trim whitespace on the image in PIL?
ImageMagick has easy support for it in the following way:
convert test.jpeg -fuzz 7% -trim test_trimmed.jpeg
I found a solution for PIL:
from PIL import Image, ImageChops
def trim(im, border):
bg = Image.new(im.mode, im.size, border)
diff = ImageChops.difference(im, bg)
bbox = diff.getbbox()
if bbox:
return im.crop(bbox)
But this solution has disadvantages:
- I need to define
border
color, it is not a big deal for me, my images has a white background - And the most disadvantage, This PIL solution doesn't support ImageMagick's
-fuzz
key. To add some fuzzy cropping. as I can have some jpeg compression artifacts and unneeded huge shadows.
Maybe PIL has some built-in functions for it? Or there is some fast solution?
Solution 1:
I don't think there is anything built in to PIL that can do this. But I've modified your code so it will do it.
- It gets the border colour from the top left pixel, using
getpixel
, so you don't need to pass the colour. - Subtracts a scalar from the differenced image, this is a quick way of saturating all values under
100, 100, 100
(in my example) to zero. So is a neat way to remove any 'wobble' resulting from compression.
Code:
from PIL import Image, ImageChops
def trim(im):
bg = Image.new(im.mode, im.size, im.getpixel((0,0)))
diff = ImageChops.difference(im, bg)
diff = ImageChops.add(diff, diff, 2.0, -100)
bbox = diff.getbbox()
if bbox:
return im.crop(bbox)
im = Image.open("bord3.jpg")
im = trim(im)
im.show()
Heavily compressed jpeg:
Cropped:
Noisy jpeg:
Cropped:
Solution 2:
Use wand http://docs.wand-py.org/en/0.3-maintenance/wand/image.html
trim(color=None, fuzz=0) Remove solid border from image. Uses top left pixel as a guide by default, or you can also specify the color to remove.
Solution 3:
using trim function at ufp.image module.
import ufp.image
import PIL
im = PIL.Image.open('test.jpg', 'r')
trimed = ufp.image.trim(im, fuzz=13.3)
trimed.save('trimed.jpg')