Are there number systems corresponding to higher cardinalities than the real numbers?

Solution 1:

First of all, let me clear a confusion of yours.

$\Bbb R$ has cardinality $2^{\aleph_0}$. This is not necessarily $\aleph_1$. It is consistent with the axioms of modern set theory that the answer is positive or negative. Similarly $2^{2^{\aleph_0}}$ need not be equal to $\aleph_2$, and it could be much larger.

Now that we cleared that issue. What is a number system? If you mean a field, simply something which has a structure of addition and multiplication like we know on $\Bbb Q$ or $\Bbb R$ or so on, then take any set $X$, and consider the ring of polynomials $\Bbb R[X]$ whose indeterminate variables come from $X$. Then $\Bbb R[X]$ is an integral domain, and therefore it has a fraction field, which is both a field and has the cardinality of $\max\{|\Bbb R|,|X|\}$. Picking a suitable $X$ would do.

If by a number system you mean something like ordinals, which are numbers (at least by virtue of being called "ordinal numbers") then ordinals have four natural operations, each defined from the previous one by transfinite induction: successorship, addition, multiplication and exponentiation.

Moreover we can show that if $\alpha$ and $\beta$ are infinite ordinals, then regardless to whatever operation you use on $\alpha$ and $\beta$, the cardinality of the result is the maximal one between $\alpha$ and $\beta$. This is wonderful, since it means that we don't have to look very far to find ordinals $\gamma$ with the property that $\{\alpha\mid\alpha<\gamma\}$ is closed under all operations.

For example, every infinite ordinal which is an initial ordinal (the least one of a given cardinality) is closed under all these operations. So $\omega_1$ and $\omega_2$ and $\omega_{\omega_1^\omega\cdot 5+\omega^{42}+1}$ are all such ordinals (recall that $\omega_\alpha$ denotes the $\alpha$-th initial ordinal). Pick any such ordinal whose cardinality is larger than the cardinality of the continuum, and you have an example.

It might be worth noting that the proper class of all ordinals is another such example, and it's not even a set!

On the other side of set theoretic number systems we have the cardinals, which again are called cardinal numbers, and these represent the size of a set. They also have the same four operations as ordinals, but now we can't define them from one another. We say that a cardinal $\kappa$ is a strong limit cardinal if whenever $\lambda<\kappa$ we have that $2^\lambda<\kappa$. This implies, amongst other things, that if $\kappa$ is a strong limit cardinal then we can show that the set of all cardinals below $\kappa$ (including the finite ones, of course) is closed under all operations on the cardinals, which will also make a number system.

And again, it might be worth noting that the class of all cardinals (what Cantor called Tav, the last letter of the Hebrew alphabet) is an example similar to the class of ordinals. It's a number system which is too large to even be a set.

Solution 2:

The surreal numbers are an ordered field too big even to be a set: they form a proper class that includes the ordinals.