Check if a file is executable
Solution 1:
Take a look at the various test operators (this is for the test command itself, but the built-in BASH and TCSH tests are more or less the same).
You'll notice that -x FILE
says FILE exists and execute (or search) permission is granted.
BASH, Bourne, Ksh, Zsh Script
if [[ -x "$file" ]]
then
echo "File '$file' is executable"
else
echo "File '$file' is not executable or found"
fi
TCSH or CSH Script:
if ( -x "$file" ) then
echo "File '$file' is executable"
else
echo "File '$file' is not executable or found"
endif
To determine the type of file it is, try the file command. You can parse the output to see exactly what type of file it is. Word 'o Warning: Sometimes file
will return more than one line. Here's what happens on my Mac:
$ file /bin/ls
/bin/ls: Mach-O universal binary with 2 architectures
/bin/ls (for architecture x86_64): Mach-O 64-bit executable x86_64
/bin/ls (for architecture i386): Mach-O executable i386
The file
command returns different output depending upon the OS. However, the word executable
will be in executable programs, and usually the architecture will appear too.
Compare the above to what I get on my Linux box:
$ file /bin/ls
/bin/ls: ELF 64-bit LSB executable, AMD x86-64, version 1 (SYSV), for GNU/Linux 2.6.9, dynamically linked (uses shared libs), stripped
And a Solaris box:
$ file /bin/ls
/bin/ls: ELF 32-bit MSB executable SPARC Version 1, dynamically linked, stripped
In all three, you'll see the word executable
and the architecture (x86-64
, i386
, or SPARC
with 32-bit
).
Addendum
Thank you very much, that seems the way to go. Before I mark this as my answer, can you please guide me as to what kind of script shell check I would have to perform (ie, what kind of parsing) on 'file' in order to check whether I can execute a program ? If such a test is too difficult to make on a general basis, I would at least like to check whether it's a linux executable or osX (Mach-O)
Off the top of my head, you could do something like this in BASH:
if [ -x "$file" ] && file "$file" | grep -q "Mach-O"
then
echo "This is an executable Mac file"
elif [ -x "$file" ] && file "$file" | grep -q "GNU/Linux"
then
echo "This is an executable Linux File"
elif [ -x "$file" ] && file "$file" | grep q "shell script"
then
echo "This is an executable Shell Script"
elif [ -x "$file" ]
then
echo "This file is merely marked executable, but what type is a mystery"
else
echo "This file isn't even marked as being executable"
fi
Basically, I'm running the test, then if that is successful, I do a grep on the output of the file
command. The grep -q
means don't print any output, but use the exit code of grep to see if I found the string. If your system doesn't take grep -q
, you can try grep "regex" > /dev/null 2>&1
.
Again, the output of the file
command may vary from system to system, so you'll have to verify that these will work on your system. Also, I'm checking the executable bit. If a file is a binary executable, but the executable bit isn't on, I'll say it's not executable. This may not be what you want.
Solution 2:
Seems nobody noticed that -x
operator does not differ file with directory.
So to precisely check an executable file, you may use
[[ -f SomeFile && -x SomeFile ]]
Solution 3:
Testing files, directories and symlinks
The solutions given here fail on either directories or symlinks (or both). On Linux, you can test files, directories and symlinks with:
if [[ -f "$file" && -x $(realpath "$file") ]]; then .... fi
On OS X, you should be able to install coreutils with homebrew and use grealpath
.
Defining an isexec
function
You can define a function for convenience:
isexec() {
if [[ -f "$1" && -x $(realpath "$1") ]]; then
true;
else
false;
fi;
}
Or simply
isexec() { [[ -f "$1" && -x $(realpath "$1") ]]; }
Then you can test using:
if `isexec "$file"`; then ... fi
Solution 4:
Also seems nobody noticed -x operator on symlinks. A symlink (chain) to a regular file (not classified as executable) fails the test.